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kvv77 [185]
4 years ago
12

an astronomer wishes to measure on a photograph the distance between the image of a certain star and three star other star image

s nearby, if 8 images are nearby how many choices of the three stars does he have?
Mathematics
1 answer:
Greeley [361]4 years ago
6 0
The astronomer has to choose 3 star images out of 8.This is a problem of combinations. This can be expressed as 8C3 i.e. combination of 8 objects taken 3 at a time.

8C3= \frac{8!}{3!*5!}=56

This means, if 8 images are nearby the astronomer will have 56 choices <span>of the three stars.</span>
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
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Reil [10]
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6 0
3 years ago
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madreJ [45]

Step-by-step explanation:

We can break this up into pieces, first we do, 7/8 - 1/4, find the least common denominator which is 8, so the equation will be 7/8 - 2/8, which we can now subtract and will give us, 5/8, now that we have done that, we can do 5/8 - 1/2. Since we know that half of 8 (our denominator) is 4. Then the equation would be 5/8 - 4/8, which brings us to 1/8 as our final answer.

Cheers!

7 0
2 years ago
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Sedaia [141]
1) we calculte the driver´s unit rate of speed.
s=speed
d=distance
t=time.

s=d/t


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x-----------------------------  1 hour

x=(45 miles * 1 hour) / (3/4 hour)=60 miles.

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2)we calculate the distance traveled at 1.25 hour.

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Answer: the driver would´t go late, because, the distance is 65 miles, and he can travel 75 miles if he drive with that speed . 
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katrin2010 [14]
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5 0
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