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marishachu [46]
2 years ago
6

I need help please !

Mathematics
1 answer:
earnstyle [38]2 years ago
5 0
No it’s not because a polynomial has a 6 not a 2
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Help me pls i want to pass my math class
kati45 [8]

Answer:

C

The slope is -2

The y-intercept is (0,1)

Slope=mx

y-intercept=b

y=mx+b

4 0
2 years ago
If the general solution of a differential equation is ​y(t)equals=Upper C e Superscript negative 4 t Baseline plus 7Ce−4t+7​, wh
Maru [420]

Answer:

y(t) = 3e^{-4t}+7

Step-by-step explanation:

y(t) = Ce^{-4t}+7

At <em>y</em>(0) = 10, when <em>t</em> = 0, <em>y</em> = 10.

y(0) = 10 = Ce^{-4\times0}+7

10 = C+7

C = 3

Hence, the solution is

y(t) = 3e^{-4t}+7

8 0
3 years ago
Read 2 more answers
I need help with this ​
zaharov [31]
Yes it’s a rectangle because the diagonals bisect each other, and they are equal in length.
7 0
2 years ago
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3. if kx² + 2x + k = -kx have equal roots, find the values of k.<br>​
crimeas [40]

Answer:

k = - \frac{2}{3} , k = 2

Step-by-step explanation:

Using the discriminant Δ = b² - 4ac

The condition for equal roots is b² - 4ac = 0

Given

kx² + 2x + k = - kx ( add kx to both sides )

kx² + 2x + kx + k = 0 , that is

kx² + (2 + k)x + k = 0 ← in standard form

with a = k, b = 2 + k and c = k , thus

(2 + k)² - 4k² = 0 ← expand and simplify left side

4 + 4k + k² - 4k² = 0

- 3k² + 4k + 4 = 0 ( multiply through by - 1 )

3k² - 4k - 4 = 0 ← in standard form

(3k + 2)(k - 2) = 0 ← in factored form

Equate each factor to zero and solve for k

3k + 2 = 0 ⇒ 3k = - 2 ⇒ k = - \frac{2}{3}

k - 2 = 0 ⇒ k = 2

5 0
3 years ago
What is The prime factorization of 464
harkovskaia [24]
4 is your answer bud
8 0
3 years ago
Read 2 more answers
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