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3 years ago

Between which two integers does square root of /51 lie

Mathematics

2 answers:

VashaNatasha [74]3 years ago

8 0

Answer:

7 and 8

Step-by-step explanation:

Consider the perfect squares either side of 51

49 < 51 < 64 , thus

$\sqrt{49}$ < $\sqrt{51}$ < $\sqrt{64}$ , that is

7 < $\sqrt{51}$ < 8

Elza [17]3 years ago

4 0

Answer:

7 and 8.

Step-by-step explanation:

7^2 = 49 and 8^2 = 64.

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One of the events in the Winter Olympics is the Men's 500-meter Speed Skating.

poizon [28]

Answer:

Mean: $\bar x = 40.61$

$Median =40.2$

$Mode = 43.4$

Step-by-step explanation:

Given

See attachment for data

Solving (a): The mean

Mean is calculated as:

$\bar x = \frac{\sum x}{n}$

From the attached:

$n = 14$

So, the mean is:

$\bar x = \frac{43.4+43.4+43.4+43.1+43.2+40.2+40.2+40.1+40.3+39.44+39.17+38.03+38.19+36.45}{14}$

$\bar x = \frac{568.58}{14}$

$\bar x = 40.61$

Solving (b): The median

$n = 14$ ; this is an even number. So, the median is:

$Median = \frac{1}{2}(n+1)$

$Median = \frac{1}{2}(14+1)$

$Median = \frac{1}{2}(15)$

$Median = 7.5th$

This implies that the median is the average of the 7th and 8th item.

Next, is to order the data (in ascending order): <em>36.45, 38.03, 38.19, 39.17, 39.44, 40.1, 40.2, 40.2, 40.3, 43.1, 43.2, 43.4, 43.4, 43.4.</em>

The 7th and 8th items are: 40.2 and 40.2

The median is:

$Median = \frac{1}{2}(40.2 + 40.2)$

$Median = \frac{1}{2}*80.4$

$Median =40.2$

Solving (c): The mode

43.4 has the highest number of occurrence.

So:

$Mode = 43.4$

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3 years ago

Tell wheter x and y show direct variation. Explain your reasoning. x = 5/8y

inessss [21]

X varies directly as y would be
$x= y(\frac{5}{8} )$

x vairies inversly as y would be
$x= y(\frac{5}{8y} )$

not sure if the y is on the bottom or on top from looking at the question

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3 years ago

# of t-shirts sold

aivan3 [116]

If x represents # tshirts sold, wouldn't it simply be: (0,0) (1, 13.50) (2, 27), etc... am I missing something?

6 0

3 years ago

Addison read 25 pages of the book the first day. She continued to read 20 pages every day. The book has 245 pages. Write an ineq

Akimi4 [234]

It should be twelve days

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3 years ago

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Find the area of the following shapes.

Virty [35]

Area of small rectange = 7 cm × 4 cm = 28 cm sq

Area of bigger rectangle = 4cm×10 cm = 40 cm sq

Area of traingle = 1/2 × 8*3 cm sq = 12 cm sq

total area of polygon = ( 28 + 40 + 12 ) cm sq

area of polygon = 80 cm sq

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3 years ago