3 years ago

Between which two integers does square root of /51 lie

Mathematics

2 answers:

VashaNatasha [74]3 years ago

8 0

Answer:

7 and 8

Step-by-step explanation:

Consider the perfect squares either side of 51

49 < 51 < 64 , thus

$\sqrt{49}$ < $\sqrt{51}$ < $\sqrt{64}$ , that is

7 < $\sqrt{51}$ < 8

Elza [17]3 years ago

4 0

Answer:

7 and 8.

Step-by-step explanation:

7^2 = 49 and 8^2 = 64.

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