Answer:
-x+4
Step-by-step explanation:
given that
(x^3-4x^2+7x-28)÷(x^2+7)
or
first (x^2+7) × -x = -x^3-7x
so (x^3-4x^2+7x-28) + (-x^3-7x) = -4x^2-28
agian (x^2+7)×(4) = 4x^2+28
so, (-4x^2-28) + (4x^2+28) = 0
hence the quotient is -x+4
the bottom one on the right
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