(x^3-4x^2+7x-28)/(x^2+7)

Mathematics

1 answer:

saw5 [17]2 years ago

6 0

Answer:

-x+4

Step-by-step explanation:

given that

(x^3-4x^2+7x-28)÷(x^2+7)

first (x^2+7) × -x = -x^3-7x

so (x^3-4x^2+7x-28) + (-x^3-7x) = -4x^2-28

agian (x^2+7)×(4) = 4x^2+28

so, (-4x^2-28) + (4x^2+28) = 0

hence the quotient is -x+4

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