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n200080 [17]
3 years ago
6

Greatest To Least -5,1, -7, 0, 6

Mathematics
2 answers:
g100num [7]3 years ago
8 0

Answer:

6,1,0,-5,-7

Step-by-step explanation:

egoroff_w [7]3 years ago
3 0
Greatest to least 6,1,0,-5,-7
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The length of a rectangle is shown below:
uranmaximum [27]

Sorry if I get this wrong but if your trying to make a rectangle wouldn't it bc (-3,1) and (1,1)?

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1/4 + 1/3= {Khan Academy btw}
zmey [24]

Answer: \frac{7}{12}

Step-by-step explanation:

\frac{1}{4} +\frac{1}{3}=\frac{(1)(3)+(4)(1)}{(4)(3)}  =\frac{3+4}{12} =\frac{7}{12}

5 0
2 years ago
Write 3x^2-18x-6 in vertex form
Vedmedyk [2.9K]
The standard form of a quadratic equation is \displaystyle{ y=ax^2+bx+c, while the vertex form is:

                      y=a(x-h)^2+k, where (h, k) is the vertex of the parabola.

What we want is to write \displaystyle{ y=3x^2-18x-6 as y=a(x-h)^2+k

First, we note that all the three terms have a factor of 3, so we factorize it and write:

\displaystyle{ y=3(x^2-6x-2).


Second, we notice that x^2-6x are the terms produced by (x-3)^2=x^2-6x+9, without the 9. So we can write:

x^2-6x=(x-3)^2-9, and substituting in \displaystyle{ y=3(x^2-6x-2) we have:

\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11].

Finally, distributing 3 over the two terms in the brackets we have:

y=3[x-3]^2-33.


Answer: y=3(x-3)^2-33
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3 years ago
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Answer:

The second one

Step-by-step explanation:

7 0
2 years ago
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