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wariber [46]
3 years ago
8

What is the Root of quantitive

Mathematics
1 answer:
Tresset [83]3 years ago
3 0

The root of an equation is the same as the solution to the equation.

:)
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Find the percentage of data points that lie between -3.01 and 2.61?<br> z= (x-u) /o
Marat540 [252]

Answer:

To find the percetage of data points that lie between the points -3.01 and 2.61, on a normal distribution we're going to need the help of a calculator. The result is: 99.42%

Attached you will find the graph that represents the result.

6 0
3 years ago
There are 32 ounces of water in a glass. Someone drinks 55% of the water. How many ounces of water are left? Answer without unit
Tanzania [10]

Answer:

14.4

Step-by-step explanation:

If someone drinks 55%, that means 45% is left over.  You multiply 32 x 45 to find out what is left.

6 0
3 years ago
Read 2 more answers
Two points move along a circle of length 120m with a constant speed. If they move in different directions, then they meet every
KiRa [710]

Let x and y be the speeds of the two points. The circle is of length 120m that is Circumference of circle is 120m.When the points are moving in opposite directions, they meet in every 15 seconds.That is the points cover 120m in 15 seconds.As they are moving in opposite directions, so the relative speed will be equal to the sum of speeds of both points.Speed= Distance ÷Time = 120÷15=8m per seconds.

x+y=8

When going in the same direction, one point catches up to the second every 60 seconds.Speed= 120÷60=2 m per seconds

x-y=2.

Solving the two equations by elimination method:

x+y=8.

x-y=2

Adding the equations:

2x=10 ,x=5m / sec.

x+y=8

5+y=8

y=3m/sec.

Thus, the speed of the two points is 5 m/s and 3 m/s.

8 0
3 years ago
5(2x+1)-2x<br><br> How to solve
kati45 [8]

Answer:

8x + 5

Step-by-step explanation:

5 * (2x+1) = 10x +5

10x + 5 -2x

8x + 5

3 0
3 years ago
In a previous exercise we formulated a model for learning in the form of the differential equation dP dt = k(M − P) where P(t) m
GalinKa [24]

Answer:

\frac{dP}{M-P}= kdt

And we can integrate both sides of the equation using the following substitution:

u= M-P, du =-dP

And replacing we got:

\int -\frac{du}{u} = kt +C

-ln (u)= kt+c

If we multiply both sides by -1 we got:

ln (u ) = -kt -c

ln (M-P) = -kt -c

And using exponential in both sides of the equation we got:

M-P = e^{-kt} e^{-c}

And solving for P we got:

P(t) = M- e^{-kt}e^{-c}

And replacing P_o =e^{-c} we got:

P(t) = M - P_o e^{-kt}

We can use the condition P(0)=0 and we got:

0 = M -P_o e^0

And we see that M = P_o and replacing we got:

P= M(1- e^{-kt})

Step-by-step explanation:

For this case we aasume the following differential equation:

\frac{dP}{dt}= k(M-P)

Is a separable differential equation so we can do the following procedure:

\frac{dP}{M-P}= kdt

And we can integrate both sides of the equation using the following substitution:

u= M-P, du =-dP

And replacing we got:

\int -\frac{du}{u} = kt +C

-ln (u)= kt+c

If we multiply both sides by -1 we got:

ln (u ) = -kt -c

ln (M-P) = -kt -c

And using exponential in both sides of the equation we got:

M-P = e^{-kt} e^{-c}

And solving for P we got:

P(t) = M- e^{-kt}e^{-c}

And replacing P_o =e^{-c} we got:

P(t) = M - P_o e^{-kt}

We can use the condition P(0)=0 and we got:

0 = M -P_o e^0

And we see that M = P_o and replacing we got:

P= M(1- e^{-kt})

8 0
3 years ago
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