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Harlamova29_29 [7]
3 years ago
8

Does anyone know what the answer is I need help pls

Mathematics
2 answers:
otez555 [7]3 years ago
6 0
24x=360
x=15
hope this helps good luck!
steposvetlana [31]3 years ago
5 0

Answer:

x=15

Step-by-step explanation:

If each of those expressions is the measure of each arc of the circle, when added together they should equal 360

8x-10+6x+10x+10=360

24x=360

x=15

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When subtracting polynomials,distribute the negative sign,then add.
Doss [256]

Answer:

7m^2 - 11m - 2

Step-by-step explanation:

Subtract (-3m^2 + 10m + 4) from 4m^2 - m + 2:

  4m^2 - m + 2

- (-3m^2 + 10m + 4)   Now distribute the negative sign:

  4m^2 - m + 2

+ 3m^2 - 10m - 4

--------------------------

   7m^2 - 11m - 2 is the final answer.

5 0
3 years ago
Allen�s hummingbird (Selasphorus sasin ) has been studied by zoologist Bill Alther A small group of 15 Allen� s hummingbirds has
Bogdan [553]

Answer:

1) 80% CI: [3.04; 3.26]gr

d= 0.11

2) n= 28 hummingbirds

Step-by-step explanation:

Hello!

The study variable of this experiment is:

X: the weight of a hummingbird. (gr)

And it has a normal distribution, symbolically: X~N(μ;σ²)

And (I hope I got it correctly) its population standard deviation is σ= 0.33

There was a sample of n= 15 hummingbirds taken, its sample mean X[bar]= 3.15 gr

1) You need to construct an 80% Confidence Interval for the population mean of the hummingbird's weight.

Since the study variable has a normal distribution, you can use either the standard normal distribution or the Student's t distribution. Both are useful to estimate the population mean. Since the population standard variance is known, the best choice is the Standard normal.

Z= <u> X[bar] - μ </u>~ N(0;1)

       σ/√n

The formula for the interval is:

X[bar] ± Z_{1- \alpha /2} * (σ/√n)

Z_{1- \alpha /2}= Z_{0.90} = 1.28

3.15 ± 1.28 * (0.33/√15)

[3.04; 3.26]gr

The margin of error (d) of a confidence interval is hal its amplitude (a)

a= Upper bond - Lower bond

d= (Upper bond - Lower bond)/2

d= \frac{(3.26-3.04)}{2} = 0.11

2) You need to calculate a sample size for a 80% Confidence interval for the average weight of the hummingbirds with a margin of error of d= 0.08

As I said before, the margin of error is half the amplitude of the interval, the formula you use to estimate the population mean has the following structure:

"point estamator" ± "margin of error"

Then the margin of error is:

d= Z_{1- \alpha /2} * (σ/√n)

Now what you have to do is rewrite the formula based on the sample size

d= Z_{1- \alpha /2} * (σ/√n)

\frac{d}{Z_{1- \alpha /2}}= σ/√n

√n * \frac{d}{Z_{1- \alpha /2}}= σ

√n = σ * \frac{Z_1- \alpha /2}{d}

n = (σ * \frac{Z_1- \alpha /2}{d})²

n=  (0.33 * \frac{1.28}{0.08})²

n= 27.8784 ≅ 28 hummingbirds.

I hope it helps!

4 0
3 years ago
What are the 3 characteristics of a polygon
Bingel [31]

Answer: The number of sides of the shape.

The angles between the sides of the shape.

The length of the sides of the shape.

Step-by-step explanation:

7 0
2 years ago
Can anybody help with this one ...... ?
VLD [36.1K]

Answer:The answer is choice 3

Step-by-step explanation:

8 0
3 years ago
Solve 3 -x = 243 -5 1/5 5
Paraphin [41]

Answer:

x=-243

Step-by-step explanation:

The equation is

-3^{-5}=\frac{1}{x}

Solve for x

we know that

-3^{-5}=-\frac{1}{3^{5}}=-\frac{1}{243}

substitute

-\frac{1}{243}=\frac{1}{x}

so

x=-243

3 0
3 years ago
Read 2 more answers
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