A machine can produce 6 yards of fabric in 2 minutes. How much fabric can the machine can produce in 1 hour

What is a equivalent fraction to 3/11

ankoles [38]

Answer:

6/22,9/33,12/44,15/55,... I mean you could go no and on...

6 0

3 years ago

Read 2 more answers

Which choice could not be a set of intervals for a frequency table of histogram?

valentina_108 [34]

When constructing the histogram, the intervals are selected in such a way that the width of each interval is the same and the gap between two intervals stays uniform throughout the histogram. This makes the data easy to visualize, easy to interpret and easy to understand.

From the given options, option B lists the intervals in an absurd order. First interval is from 0 to 3. There is no gap between first and second interval and the second interval is larger than the first. So these intervals cannot be the set of intervals of a histogram.

So, the answer to this question is option B

6 0

4 years ago

X and y are in direct proportion, when x is 8, y is 12. Which of the following is not a

Nat2105 [25]

Answer:

d.

Step-by-step explanation:

if x varies directly as y,

x = ky

8 = 12k

12k = 8

k = 8/ 12

k = 2/3,

x = 2/3 y

now substitute the value of any of the numbers of each pair, and check if it works:

for e.g, find x when y = 15

x = 2/3y

x = 2/3 × 15

x = 10

since you obtain x = 10 when y = 15, the pair is a possible corresponding value of x and y. now do the same for the rest .

ii) x = 2/3y

x = 2/3 × 3, when y = 3

x = 2

hence, this is also a possible pair of x and y values.

iii) x = 2/3y

x = 2/3 × 9 when y = 9

x = 6

again, a possible pair of x and y values.

iv) x = 2/3y

x = 2/3 × 20 when y = 20

x = 40/3

here, when y = 20, x is not 15. it is 40/3.

thus, it can be determined that this is not a possible pair of x and y values.

please try to understand and have a great day!

8 0

2 years ago

MATH IS HARD. HELP<br> Change the following into a single fraction: 1− (a+b/a−b)

lianna [129]

Answer:

-2b/(a-b)

Step-by-step explanation:

1− (a+b/a−b)

We need to get a common denominator of a-b

1 = (a-b)/(a-b)

Replace 1 with (a-b)/(a-b)

(a-b)/(a-b) - (a+b)/(a-b)

Put over the common denominator

(a-b) - (a+b)

-----------------

(a-b)

Distribute the minus sign.

(a-b) - a-b)

-----------------

(a-b)

a-a-b-b

---------------

a-b

-2b

----------

a-b

6 0

3 years ago

Hypothesis Testing for Means with Small Samples

Scorpion4ik [409]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is

X: volume of root beer in a Windsor Bottling Company can.

A sample of n=24 cans was taken and their contents measured, resulting:

X[bar]= 11.4 oz

S= 0.62 oz

Assuming that the variable has a normal distribution X~N(μ;σ²), the parameter of interest is the average contents of the root beer cans of the Windsor Bottling Company (μ)

The claim is that the population mean content of the cans is different from 12 oz, symbolically: μ ≠ 12

The statistical hypothesis (Null and alternative) have to be complementary, exhaustive and mutually exclusive. The null hypothesis is the "no change" hypothesis and always carries the "=" sign.

If the claim is μ ≠ 12, its complement is μ = 12, the expression carrying the "=" sign will be the null hypothesis and its complement will be the alternative hypothesis:

H₀: μ = 12

H₁: μ ≠ 12

α: 0.05

To test the population mean of this normal population, you have to apply a one sample t-test, with statistic:

$t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}$

$t_{H_0}= \frac{11.4-12}{\frac{0.62}{\sqrt{24} } } = -4.74$

This test is two-tailed, using the critical value approach, you have to determine two rejection regions. Meaning, you'll reject the null hypothesis to small values of the statistic or to high values of the statistic.

$t_{n-1;\alpha /2}= t_{23;0.025}= -2.069$

$t_{n-1;1-\alpha /2}= t_{23;0.975}= 2.069$

The decision rule is:

If $t_{H_0}$ ≤ -2.069 or if $t_{H_0}$ ≥ 2.069, then you reject the null hypothesis.

If -2.069 < $t_{H_0}$ < 2.069, then you do not reject the null hypothesis.

The value is less than the left critical value, the decision is to reject the null hypothesis.

Then you can say that with a 5% significance level, there is significant evidence to reject the null hypothesis, then the average amount of root beer of the Windsor Bottling Company is different from 12 oz, this means that the claim about the amount of root beer in the cans is correct.

I hope it helps!

6 0

4 years ago