Answer:
5>18 and 25
1 and 4>32
3<8
13<4
4<9
i hope this helped :)
Step-by-step explanation:
Answer:
f(x)=x^2+3
f(x+y)=(x+y)^2+3
this is done by replacing x with (x+y)
f(x+y)=x^2+2xy+y^2+3
therefore : f(x+y)= x^2+y^2+2xy+3
You only need to look at the y intercepts.
-11 - -7 is -4, but you can't have a negative distance so it's just 4
<h3>
Answer: 5</h3>
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Work Shown:
x^2 - 5x + 1 = 0
x^2 + 1 - 5x = 0
x^2 + 1 = 5x
(x^2 + 1)/x = 5 .... where x is nonzero
(x^2)/x + (1/x) = 5
x + (1/x) = 5
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An alternative method involves solving the original equation using the quadratic formula. After you get the two roots x = p and x = q, you should be able to find that p + 1/p = 5 and also q + 1/q = 5 as well.
In this case,
p = (5 + sqrt(21))/2
q = (5 - sqrt(21))/2
Answer:
8
Step-by-step explanation:
0 has no value what so ever when adding and subtracting.
