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Kobotan [32]
4 years ago
7

Factorize 2x^4-7x^3-13x^2+63x-45 using factor theorem.

Mathematics
1 answer:
zheka24 [161]4 years ago
8 0
Find the possible rational roots and use synthetic division to find the first zero.
I chose x=1 (which represents the factor "x-1")

1║2  -7  -13    63  -45
  ║     2    -5  -18    45
    2  -5  -18    45    0
(x-1) is a factor, (2x³ - 5x² - 18x + 45) is the other factor.

Use synthetic division on the decomposed polynomial to find the next zero.
I chose x = 3 (which represents the factor "x-3")

3║2  -5  -18    45 
  ║     6     3   -45   
    2   1  -15     0   

Using synthetic division, we discovered that (x-1), (x-3), & (2x² + x -15) are factors.  Take the new decomposed polynomial (2x² + x -15) and find the last two factors using any method.

Final Answer: (x-1)(x-3)(x+3)(2x-5)




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Answer:Your calculator should now display a screen with these variables. I have written what each

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Step-by-step explanation:

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The probability is 1 in 4,011,000 that a single auto trip in the United States will result in a fatality. Over a lifetime, an av
IrinaVladis [17]

Answer:

0.0114

Step-by-step explanation:

(a) What is the probability of a fatal accident over a lifetime?

Suppose A be the event of a fatal accident occurring in a single trip.

Given that:

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Then;

P(A) = 1/4011000

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Now;

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P(\mathbf{\overline A}) = 1 -  P(A)

P(\mathbf{\overline A}) = 1 - 2.493 × 10⁻⁷

P(\mathbf{\overline A}) = 0.9999997507

However, P(fatal accident over a lifetime) = P(at least 1 fatal accident in lifetime i.e. 46000 trips)

= 1 - P(NO fatal accidents in 46000 trips)

Similarly,

P(No fatal accidents over a lifetime) = P(No fatal accident in the 46000 trips) = P(No fatality on the 1st trip and No fatality on the 2nd trip ... and no fatality on the 45999 trip and no fatality on the 46000 trip)

= [P(\overline A)] ^{46000}  \ \ \  (since \  trips \ are \ independent \ events)

= [0.9999997507]^{46000}

= 0.9885977032

Finally;

P(fatal accident over a lifetime) = 1 -  0.9885977032

P(fatal accident over a lifetime) = 0.0114022968

P(fatal accident over a lifetime) ≅ 0.0114

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