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3 years ago

CA and CB name the same ray. True False

Mathematics

1 answer:

Maru [420]3 years ago

4 0

Answer:

I think is true good luck

Step-by-step explanation:

You might be interested in

What's the area if an equilateral triangle with sides of 10 inches and height of 7 inches

Hitman42 [59]

Formula: (Base * Height) / 2 = Area

(10 * 7) / 2 =
70 / 2 =35 inches squared

Hope I helped

ΩΩΩΩΩΩΩΩΩΩ

7 0

3 years ago

Tres hermanos van a repartirse un pastel y medio, cuanto le toco de pastel a cada uno de los hermnos

Anna71 [15]

Answer:

medio pastel cada uno

Step-by-step explanation:

Hay 3 hermanos, si decimos que un pastel entero tiene 6 pedazos entonces su fraccion seria 6/6. Si dividimos este pastel entre los tres hermanos cada uno tendria...

$\frac{6 / 3}{6}$ = $\frac{2}{6}$

Medio pastel seria la mitad de 6/6 que seria 3/6. Si dividimos esto entre los 3 hermanos cada uno tendria...

$\frac{3 / 3}{6} = \frac{1}{6}$

Ahora que dividimos los 2 pasteles tenemos que unir las fracciones para saber cuanto pastel le toco a cada hermano...

$\frac{2}{6} + \frac{1}{6} = \frac{3}{6}$ o medio pastel cada uno

8 0

2 years ago

How many time 2/3 can go into 16<br><br> Explanation pls!!

tensa zangetsu [6.8K]

Answer:

24 times

Step-by-step explanation:

16 divided by 2/3 is 24

hope this helped!

7 0

1 year ago

Can you plz help me i need it

Snowcat [4.5K]

Answer:

v= -2

Step-by-step explanation:

2v + 7 = 3

(-7 both sides)

2v = -4

(divide bu 2 on both sides)

v = -2

hope this helps!!!!! :)

3 0

3 years ago

Consumer products are required by law to contain at least as much as the amount printed on the package. For example, a bag of po

Troyanec [42]

Answer:

The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

Step-by-step explanation:

We are given that

Standard deviation, $\sigma=0.2$ ounces

We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.

$P(x\geq 10)=0.99$

Assume the bag weight distribution is bell-shaped

Therefore,

$P(\frac{x-\mu}{\sigma}\geq 10)=0.99$

We know that

$z=\frac{x-\mu}{\sigma}$

Using the value of z

Now,

$\frac{10-\mu}{0.2}=0.99$

$10-\mu=0.99\times 0.2$

$\mu=10-0.99\times 0.2$

$\mu=9.802$

Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

5 0

2 years ago