Question

If x=2y=4z, express

Answer 1

$x = 4z$

$2y = 4z$

Dividing both sides by two,

$y = 2z$

OK, part 1.

$x+4y+z = 4z + 4(2z) +z = 13z$

When $z=2$ then $x+4y+z =13(2)=26$

Part 2.

$2x+3y+2z= 2(4z) +3(2z) + 2z = 16z$

When $z=2$ then $2x+3y+2z=16(2)=32$