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Solnce55 [7]
3 years ago
8

Sam can prepare 20 wall paintings in four weeks.How much time will he need to prepare 80 wall paintings

Mathematics
1 answer:
solniwko [45]3 years ago
4 0

Note how 80 is four times 20. So, 4*4=16. Sam can prepare 80 wall paints in 16 weeks.

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A tent was marked up 150% from an original cost of $52. Last Friday, Ethan bought the tent and paid an additional 10% in sales t
BARSIC [14]

$143

First you would have to find out the price that the tent was bumped up to.

52*150%=78

You then add the answer to your original price.

52+78=130

You then have to find the sales tax. You do this by multiplying 10% to your new price.

130*10%=13

You then have to add the sales tax to your number.

130+13=143

$143 is your answer.

4 0
3 years ago
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Sam bought brushes for 8$ a palette for 5$ and oil paints for 15$ he paid 29.82$ all together what sale tax rate did Sam pay
Sonja [21]

Answer:

$1.82

Step-by-step explanation:


5 0
4 years ago
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On a mountain, the temperature decreases by 18°F every 5000 feet. What integer represents the change in temperature at 20,000 fe
gizmo_the_mogwai [7]
18 times 4 = 72

Because 5000 times 4 = 20,000

The change in temp. is -72degrees
8 0
3 years ago
A chemical engineer is trying to increase the amount of the useful product in a reaction. She performs the reaction with her new
Natali5045456 [20]

Answer:

I think ur missing the actual data mate

Step-by-step explanation:

8 0
3 years ago
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Someone help please!!!
Ne4ueva [31]

Answer:

41.5 ft

Step-by-step explanation:

From the information given, and definition of midpoint, we know that:

AB = BC = ½ AC

AC = CE = ½ AE

CD = DE = ½ CE

GF = FE = ½ GE

HG = GE = ½ HE

AI = IH = ½ AH

AJ = JI = ½ AI

We also know:

AH = 20

HE = 14

GD = 4

Therefore:

AI = IH = 10

HG = GE = 7

AJ = JI = 5

GF = FE = 7/2

Next, since JB and IC are parallel with HE, we know that AJB and AIC are similar to AEH.  So:

JB / 5 = 14 / 20

JB = 7/2

IC / 10 = 14 / 20

IC = 7

And since DF and CG are parallel to AH, then DFE and DGE are similar to AHE.  So:

DF / (7/2) = 20 / 14

DF = 5

CG / 7 = 20 / 14

CG = 10

Next we know that AIB and AHC are similar, and DEG and CEH are similar.

IB / 10 = CH / 20

CH / 14 = 4 / 7

CH = 8, IB = 4.

We've found all the lengths inside triangle AEH.  Adding them up:

JB + IB + IC + CH + CG + DG + DF

7/2 + 4 + 7 + 8 + 10 + 4 + 5

41.5

The total length of the inside bars is 41.5 ft.

6 0
4 years ago
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