The approximate solution you require is the x coordinate of the point of intersection of the 2 graphs.
<u>Answer:</u>
<h2>
P = (6-π)/6</h2>
<u>Explanation:</u>
Circle Area:
CA = 1²×π
CA ≈ π in²
Triangle Area:
TA = 3×4/2 = 6 in²
Probability:
P(point not in circle) = (6-π)/6 ≈ 0.48 ≈ 47.64%
Replace a and b with their given values:
(2(3/5) -1/3) / -6.75/15
2 x 3/5 = 6/5
6/5 - 1/3 = 18/15 - 5/15 = 13/15
13/15 / -6.75/15 = 13/15 x 15/-6.75 = (13 x 15) / (15 x -6.75) = 195/-101.25 = -1 25/27
Answer: -1 and 25/27
Which set of data best represents a normal distribution? 2, 3, 3, 4, 4, 4, 5, 5, 6 3, 4, 5, 6, 6, 7, 7, 7, 8, 8, 9, 10 0.9, 1.0,
GuDViN [60]
2, 4, 5, 5, 6, 6, 7, 7, 7, 8, 8, 9, 9, 10
I believe the closest possible answer to this question are these numbers. Normal distribution graph needs to have a good bell-shaped figure. Thank you for your question. Please don't hesitate to ask in Brainly your queries
Answer: b
Step-by-step explanation:
