Let's look at the second equation and try multiplying it by 4:
4 * (3x + ky) = 4 * 27
Which gives us:
12x + 4ky = 108
This looks almost exactly like the first equation except that instead of -20y, there is 4ky. We could try making them equal to each other and solving for k:
-20y = 4ky
-20 = 4k
k = -5
Then, the answer is k = -5.
Answer:
similar-SAS
Step-by-step explanation:
The answer to your problem would be 38/ 45.
Distribute ^3 to both 6 and k^3
6^3 = 6 x 6 x 6 = 216
(k^3)^3 = k^9 (because you are multiplying k^3 x k^3 x k^3)
216k^9, or C) is your answer
hope this helps
Answer:
third option
Step-by-step explanation:
Using De Moivre's theorem
(
+ i)³ , then
|
+ i |
= ![\sqrt{(\sqrt{3})^2+1^2 }](https://tex.z-dn.net/?f=%5Csqrt%7B%28%5Csqrt%7B3%7D%29%5E2%2B1%5E2%20%7D)
=
=
= 2
arg(
+ i) =
(
) = ![\frac{\pi }{6}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7B6%7D)
Thus
(
+ i)³
= 2³ [ cos(3 ×
) + isin( 3 ×
) ]
= 8 [ cos(
) + isin(
) ]