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Dahasolnce [82]
2 years ago
7

If R(x) and S(x) are inverse functions, which statement must be true? A) R(S(X))=1 B) R(S(X))=X C) R(X) R(X)= 1/S(x) D) R(x)=-S(

x)
Mathematics
2 answers:
Aliun [14]2 years ago
7 0
The answer will be B)R(S(X))=X
Irina-Kira [14]2 years ago
3 0

<u>ANSWER:</u> The correct answer is R(S(x))=x.


<u>Explanation</u>

The composition of a function of x and its inverse will produce the independent variable x.


For instance, let f(x)=2x.

The inverse of this function is f^{-1}(x)=\frac{x}{2}.


If we compose these two functions, we will obtain;


(f\circ f^{-1})(x)=f(f^{-1}(x))


This means we have to substitute the whole inverse function in to the function itself.

(f\circ f^{-1})(x)=f(f^{-1}(x))=2(\frac{x}{2})=x


The other way round will also produce the same result.


Thus;

(f^{-1}\circ f(x)=f^{-1}(f(x))=(\frac{2x}{2})=x


This does not only apply to the given example it applies to all functions and their inverse.





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So, the volume of the shoebox is

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10a. Each shoebox has a volume of 22 cubic inches. <span>False. The volume is 228 cubic inches.

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Each term above describes the term below, but the term below doesn't necessarily describe the term above.

The choice of terms is : <span>trapezoid</span>, <span>triangle</span>, <span>rhombus</span>, <span>parallelogram</span>

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Trapezoid - A four sided shape with a pair opposite parallel sides.<span>
Triangle - </span>A shape with three sides.<span>
Rhombus - </span>A shape with four equal straight sides<span>.
Parallelogram - </span>A quadrilateral with two sets of parallel sides.<span>
Quadrilateral - </span>A four-sided shape with four angles.<span>
Square - </span>A four-sided shape with all four sides the same length, and all four angles are the same size.

The first term is quadrilateral. From this, we can determine that the term <span>triangle</span> won't be used at all, as it's a three-sided figure, whereas a <span>quadrilateral</span> is a four-sided figure. This leaves <span>trapezoid, rhombus, </span>and <span>parallelogram </span>as our terms.

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