Answer:
13 times 2
52 divided by 2
20 plus 6
Step-by-step explanation:
Answer:
y=2x+14
Step-by-step explanation:
y=mx+b
hope its right
Answer:
1 cm=8 km
Step-by-step explanation:
We can use a ratio to determine the scale. Take the distance on the map on the left and the "real distance" on the right
6 cm=48 km
Divide by 6
6 cm/ 6 = 48 km /6
1 cm=8 km
Answer:
18.7939 m
Step-by-step explanation:
-Let x be the distance between John and clock tower.
-Let y be the vertical distance from the eyes of the two men standing to the top of the clock tower.
#Taking the right triangle ACD:
![\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 60\textdegree=\frac{y+1.5}{x}\\\\y=x \ Tan \ 60\textdegree -1.5](https://tex.z-dn.net/?f=%5CTan%20%5C%20theta%3D%5Cfrac%7BPerpendicular%20%5C%20Height%7D%7BBase%7D%5C%5C%5C%5CTan%20%5C%2060%5Ctextdegree%3D%5Cfrac%7By%2B1.5%7D%7Bx%7D%5C%5C%5C%5Cy%3Dx%20%5C%20Tan%20%5C%2060%5Ctextdegree%20-1.5)
#Taking the right triangle ABD:
![\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 40\textdegree=\frac{y+1.5}{x+20}\\\\y=(x+20)\ Tan \ 40\textdegree -1.5](https://tex.z-dn.net/?f=%5CTan%20%5C%20theta%3D%5Cfrac%7BPerpendicular%20%5C%20Height%7D%7BBase%7D%5C%5C%5C%5CTan%20%5C%2040%5Ctextdegree%3D%5Cfrac%7By%2B1.5%7D%7Bx%2B20%7D%5C%5C%5C%5Cy%3D%28x%2B20%29%5C%20Tan%20%5C%2040%5Ctextdegree%20-1.5)
#We equate the two yo solve for x and y;
![(x+20)\ Tan \ 40\textdegree -1.5=x\ Tan \ 60\textdegree -1.5\\\\(x+20)\ Tan \ 40\textdegree=x\ Tan \ 60\textdegree\\\\0.8391x+16.7820=1.7321x\\\\x=18.7939](https://tex.z-dn.net/?f=%28x%2B20%29%5C%20Tan%20%5C%2040%5Ctextdegree%20-1.5%3Dx%5C%20Tan%20%5C%2060%5Ctextdegree%20-1.5%5C%5C%5C%5C%28x%2B20%29%5C%20Tan%20%5C%2040%5Ctextdegree%3Dx%5C%20Tan%20%5C%2060%5Ctextdegree%5C%5C%5C%5C0.8391x%2B16.7820%3D1.7321x%5C%5C%5C%5Cx%3D18.7939)
Hence, John's distance from the tower's base is 18.7939 m
Answer:
The value of radius is 7.5 units
Step-by-step explanation:
Given that a line that pass through the origin and form a triangle is a right-angle triangle. So in order to find the diameter/hypotenuse, you have to use Pythogaras Theorem :
![{c}^{2} = {a}^{2} + {b}^{2}](https://tex.z-dn.net/?f=%20%7Bc%7D%5E%7B2%7D%20%20%3D%20%20%7Ba%7D%5E%7B2%7D%20%20%2B%20%20%7Bb%7D%5E%7B2%7D%20)
Let a = 12 units,
Let b = 9 units,
Let c = hypo.,
![{hypo.}^{2} = {12}^{2} + {9}^{2}](https://tex.z-dn.net/?f=%20%7Bhypo.%7D%5E%7B2%7D%20%20%3D%20%20%7B12%7D%5E%7B2%7D%20%20%2B%20%20%7B9%7D%5E%7B2%7D%20)
![{hypo.}^{2} = 225](https://tex.z-dn.net/?f=%20%7Bhypo.%7D%5E%7B2%7D%20%20%3D%20225)
![hypo. = \sqrt{225}](https://tex.z-dn.net/?f=hypo.%20%3D%20%20%5Csqrt%7B225%7D%20)
![hypo. = 15 \: \: units](https://tex.z-dn.net/?f=hypo.%20%3D%2015%20%5C%3A%20%20%5C%3A%20units)
We have found out that the hypotenuse of the triangle is the diameter of circle. So in order to find radius, you have to divide it by 2 :
![radius = diameter \div 2](https://tex.z-dn.net/?f=radius%20%3D%20diameter%20%5Cdiv%202)
![radius = 15 \div 2](https://tex.z-dn.net/?f=radius%20%3D%2015%20%5Cdiv%202)
![radius = 7.5 \: \: units](https://tex.z-dn.net/?f=radius%20%3D%207.5%20%5C%3A%20%20%5C%3A%20units)