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Ierofanga [76]
3 years ago
15

HELP PLEASE ITS DUE TODAY!I'll give brainliest.

Mathematics
1 answer:
SOVA2 [1]3 years ago
4 0

Answer:

930=9 hundreds 3 tens

93times10

80=8 tens

320= 3 hundreds 2 tens

8000=8 thousands

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Write the ratio in simplest form: 2 pints to 2 gallons.
ryzh [129]

Answer:

2 pints: 0.25 gallons

16 pints: 2 gallons

Step-by-step explanation:

1 gallon = 0.125 pints

5 0
3 years ago
2.4 + 5.4q – 4.5q + 3.6<br><br> a.6+1.1q<br> b.9.9q+6<br> c.0.9q+6<br> d.9.9q-6
Yuri [45]
You have to add the same kind of terms, in this case the ones that have a variable (5.4q and -4.5q) and the ones that don't (2.4 and 3.6), like this:

(5.4q - 4.5q) + (2.4 + 3.6) = 0.9q + 6

The answer is c. 0.9 +6

8 0
3 years ago
What is the value of n? <br> n/-3 - 2 = -18
SCORPION-xisa [38]

Answer:

48

Step-by-step explanation:

n/-3=-16

n=-16*-3

n=48

4 0
3 years ago
Read 2 more answers
Find the volume of a right circular cone that has a height of 16.8 in and a base with a
alexgriva [62]

Answer:

Volume of right circular cone is 388.43 in³

Step-by-step explanation:

Height of circular cone = 16.8 in

Radius of circular cone = 4.7 in

We need to find Volume of right circular cone

The formula used for calculating volume of a right circular cone is: Volume=\pi r^2\frac{h}{3}

Putting values and finding volume

Volume=\pi r^2\frac{h}{3}\\Volume=3.14\times (4.7)^2 \times \frac{16.8}{3}\\Volume=3.14\times 22.09 \times 5.6\\Volume= 388.43 \:in^3

So, Volume of right circular cone is 388.43 in³

5 0
2 years ago
Box of 15 gadgets is known to contain 5 defective gadgets if 4 gadgets are drawn at random what is the probability of finding no
baherus [9]

To solve this problem, we make use of the Binomial Probability equation which is mathematically expressed as:

P = [n! / r! (n – r)!] p^r * q^(n – r)

where,

n = the total number of gadgets = 4

r = number of samples = 1 and 2 (since not more than 2)

p = probability of success of getting a defective gadget

q = probability of failure = 1 – p

 

Calculating for p:

p = 5 / 15 = 0.33

So,

q = 1 – 0.33 = 0.67

 

Calculating for P when r = 1:

P (r = 1) = [4! / 1! 3!] 0.33^1 * 0.67^3

P (r = 1) = 0.3970

 

 

Calculating for P when r = 2:

P (r = 2) = [4! / 2! 2!] 0.33^2 * 0.67^2

P (r = 2) = 0.2933

 

Therefore the total probability of not getting more than 2 defective gadgets is:

P = 0.3970 + 0.2933

P = 0.6903

 

Hence there is a 0.6903 chance or 69.03% probability of not getting more than 2 defective gadgets.

5 0
3 years ago
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