Question

If a rectangle measures 20 meters by 48 meters, what is the length, of the diagonal of the rectangle? Can you help me with this one ?

Answer 1

$the \ width \ of \ the \ rectangle : \ w=20 \ m \\ \\ the \ length \ of \ the \ rectangle : \ l=48 \m \\ \\ Diagonal : \ \sqrt{w^2 + l^2}\\ \\D =\sqrt{20^2 + 48^2} \\ \\D=\sqrt{400+2304}=\sqrt{2704}= 52 \ m$