95feet covert to meters to the nearest tenth

If the nth term of a sequence is 3n+2 them T³= T⁵=T¹⁵=

Katena32 [7]

Answer:

T^75

Step-by-step explanation:

3 times 5 = 15

5 times 15 = 75

7 0

3 years ago

Find the determinant of this matrix:

Bogdan [553]

Answer:

40

Step-by-step explanation:

$\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] = ad-bc$

4 0

1 year ago

Read 2 more answers

Y=3x-1 substitute -3 for x

Brums [2.3K]

The answer should be -10

5 0

3 years ago

Use a double number line to answer Problem 1-5.

natita [175]

Answer:

900 cans and bottles.

Hope that helps!

Step-by-step explanation:

360 / 4 = 90

90 x 100 = 900

Hope that helps!

6 0

2 years ago

The number of people arriving for treatment at an emergency room can be modeled by aPoisson process with a rate parameter of 5/h

saveliy_v [14]

Answer:

(a) The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is 3.75 arrivals.

Step-by-step explanation:

(a) If the arrivals can be modeled by a Poisson process, with λ = 5/hr, the probability of having exactly four arrivals during a particular hour is:

$P(X=4)=\frac{\lambda^{X}*e^{-\lambda} }{X!} =\frac{5^{4}*e^{-5} }{4!}=\frac{625*0.006737947}{24} =\frac{4.211}{24}=0.1754$

The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour can be written as

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))$

Using

$P(X)=\frac{\lambda^{X}*e^{-\lambda} }{X!}$

We get

$P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))\\P(X>3)=1-(0.0067+ 0.0337+ 0.0842 + 0.1404 )\\P(X>3)=1-0.2650=0.7350\\$

The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is

$EV=\lambda*t=5*0.75=3.75$

8 0

2 years ago