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3 years ago

How does the labrador current affect the climate of canada and greenland

1 answer:

max2010maxim [7]3 years ago

3 0

The Labrador current affects the climate of Canada and Greenland because it creates one of the densest concentrations of fog in the world occurs.

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2. Nitrogen has two naturally occurring

kvv77 [185]

Answer:

Suppose that:

Mass of N-14= 14

and Mass of N-15= 15

fraction N-14 x 14 + fraction N-15 x 15 = 14.007

now.. if the fractions were =, that is if fraction N-14 = fraction N-15 = 0.5, then...

0.5 x 14 + 0.5 x 15 = 14.5

more N-15 would make that number larger...

0.3 x 14 + 0.7 x 15 = 14.7

let x = abundance of N-14, then (1-x) = abundance of N-15, and we could solve for x.

(X)x14 + (1-X)x 15 = 14.007

14X + 15 - 15X = 14.007

X = 0.993

the relative abundance of N-14 = 99.3%

the relative abundance of N-15 = 0.7%

So, according to the above explanation N-14 is abundant

Explanation:

Suppose that:

Mass of N-14= 14

and Mass of N-15= 15

fraction N-14 x 14 + fraction N-15 x 15 = 14.007

now.. if the fractions were =, that is if fraction N-14 = fraction N-15 = 0.5, then...

0.5 x 14 + 0.5 x 15 = 14.5

more N-15 would make that number larger...

0.3 x 14 + 0.7 x 15 = 14.7

let x = abundance of N-14, then (1-x) = abundance of N-15, and we could solve for x.

(X)x14 + (1-X)x 15 = 14.007

14X + 15 - 15X = 14.007

X = 0.993

the relative abundance of N-14 = 99.3%

the relative abundance of N-15 = 0.7%

So, according to the above explanation N-14 is abundant

8 0

3 years ago

What is kinetic energy of a 100 kg object that is moving with a speed of 15 m/s

elena-s [515]

Answer:

16875 Joules

Kg m^2 s^-2 = Joule ,so The kinetic energy of a body of mass 150 Kg moving at 15m/s is 16875 Joules.

Explanation:

6 0

3 years ago

CHEM HELP ASAP!! <br><br> What mass of H2 would be needed to produce 208 kg of methanol?

Eddi Din [679]

So if we use the equation:

$CO+2H_{2}$ → $CH_{3}OH$

We can then determine the amount of $H_{2}$ needed to produce 208 kg of methanol.

So let's find out how many moles of methanol 208 kg is:

Methanol molar weight = 32.041g/mol

So then we can solve for moles of methanol:

$208kg*\frac{1,000g}{1kg} *\frac{1mol}{32.041g} =6,491.68mol$

So now that we have the amount of moles produced, we can use the molar ratio (from the balanced equation) of hydrogen and methanol. This ratio is 2:1 hydrogen:methanol.

Therefore, we can set up a proportion to solve for the moles of hydrogen needed:

$\frac{2}{1} =\frac{x}{6,491.68}$

$x=12,983.36mol$

So now that we have the number of moles of $H_{2}$ that are produced, we can then use the molar weight of hydrogen to solve for the mass that is needed: