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Gala2k [10]
3 years ago
12

Formula for ammonuim phostphate

Chemistry
1 answer:
DIA [1.3K]3 years ago
7 0

Answer:

(NH4)3PO4

Explanation:

ammonium has valency +1 and phosphate has valenvy -3

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Can someone pls help me with this question?:
dangina [55]

Answer:

James Chadwick

Explanation:

In his first experiment, Rutherford was unable to predict the total mass of nucleus. He noticed that if only electrons and protons are present in the nucleus then by adding their masses, it falls short of the net mass of the atom. so he concluded that there must be another particle and that Particle was later discovered by James Chadwick in 1932.

6 0
3 years ago
Does anyone know if these are correct? if not can anyone tell me what the answers are?
Stells [14]

Answer:

16. correct

17. correct

18. correct

19. correct

4 0
3 years ago
When vinegar is added to some marble chips ( calcium carbonate) bubbles of gas are observed, what gas is produced and how can it
Scrat [10]

Answer:

By passing the gas through lime water

Explanation:

The equation of the reaction of vinegar with  calcium carbonate in the form of marble chips is shown below;

CaCO3(s) + 2CH3COOH(aq) ---------> Ca(CH3COO)2(aq) + H2O(l) + CO2(g).

We can see from the reaction equation that the gas produced is carbon dioxide. This gas is identified by passing the gas through lime water. If lime water turns milky, then the gas is truly carbon dioxide.

7 0
3 years ago
Pleeeeeeeeeeeeeeeeeeas help
SIZIF [17.4K]

Answer:

For young organic materials, the carbon-14 (radiocarbon) method is used. The effective dating range of the carbon-14 method is between 100 and 50,000 years.

Explanation:

The answer is the explanation.

4 0
2 years ago
An atom emits of wavelength 1.08 meters. what is the energy change occurring in the Atom due to this emission? (Planck’s constan
butalik [34]

To answer this question, we can use the following equation:

e=\frac{h*c}{lambda}

where e is the energy change, h is Planck's constant, c is the speed of light (m/s), and lambda is wavelength in meters. So then we can plug in the information:

e=\frac{(6.626x10^{-34}J*s)(2.998x10^{8}\frac{m}{s})}{1.08m}

e=\frac{1.9865x10^{-25}J}{1.08}

e=1.84x10^{-25}J

So the energy that is omitted by the atom is 1.84x10^{-25}J.

5 0
3 years ago
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