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Shkiper50 [21]
3 years ago
13

For the following substitution reaction, which statement is FALSE? The use of a polar aprotic solvent will enhance the rate. The

process is bimolecular. The reaction proceeds via a carbocation intermediate. Increasing the concentration of hydroxide will cause an increase in the rate of reaction.
Chemistry
1 answer:
castortr0y [4]3 years ago
6 0

Answer:

FALSE: The reaction proceeds via a carbocation intermediate.

Explanation:

There is a large increase in the speed of the reaction when changing from a protic solvent to an aprotic one. This difference arises from acid / base reactions between protic solvents, which do not occur with aprotic solvents, and strong nucleophiles.

It is a reaction with 2nd order kinetics, this means that the velocity determining step is bimolecular, that is, the hydroxide ion and methyl bromide are involved in the transition state.

It is a concerted reaction, that is, in a single step, where the hydroxide ion acts as a nucleophile using its electron pair and attacks the carbon on the side opposite the link with the leaving group. In the transition state the nucleophile and the leaving group are partially attached to the carbon undergoing the reaction.

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Is salt water solution a homogeneous mixture
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yes, it is a homogeneous mixture because the different parts cannot be seen.

Explanation:

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In the following reaction, how many grams of carbon dioxide will be produced by 100 grams of ethylene (C2H4)? Click the equation
faltersainse [42]
Ethene on combustion reaction produces CO₂ and H₂O,

                     C₂H₄  +  3 O₂   →    2 CO₂  +  2 H₂O

According to Equation,

             28.05 g (1mole) C₂H₄ produced  =  88 g (2 mole) of CO₂
So,
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                                     X  =  (100 g × 88 g) ÷ 28.05 g

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3 years ago
What is the name of alkane having seven carbons atoms in the chain????
alekssr [168]

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3 years ago
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Calculate the vapor pressure in torr of a solution containng 24.5 g of glycerin (C3H8O3) in 135 mL water at 30.0* C; the vapor p
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3 0
3 years ago
Calculate the concentration of an aqueous solution of ca(oh)2 that has a ph of 11.30.
Aleks [24]
Answer:
[OH]- = 501.187 M

Explanation:
First, the given Ca(OH)2 is a base and not an acid. Therefore, we cannot do the calculations based on the pH vale. We need to get the pOH value.
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Now, pOH is calculated as follows:
pOH = -log [OH]
This means that:
2.7 = - log [OH]
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[OH]- = 501.187 M

Hope this helps :)
3 0
4 years ago
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