Answer:
yes, it is a homogeneous mixture because the different parts cannot be seen.
Explanation:
Ethene on combustion reaction produces CO₂ and H₂O,
C₂H₄ + 3 O₂ → 2 CO₂ + 2 H₂O
According to Equation,
28.05 g (1mole) C₂H₄ produced = 88 g (2 mole) of CO₂
So,
100 g of C₂H₄ will produce = X g of CO₂
Solving for X,
X = (100 g × 88 g) ÷ 28.05 g
X = 313. 72 g of CO₂
Psolution = X · PH_20
= 0.966 · 31.8 torr
= 30.7 torr
Answer:
[OH]- = 501.187 M
Explanation:
First, the given Ca(OH)2 is a base and not an acid. Therefore, we cannot do the calculations based on the pH vale. We need to get the pOH value.
pH + pOH = 14
11.3 + pOH = 14
pOH = 14 - 11.3 = 2.7
Now, pOH is calculated as follows:
pOH = -log [OH]
This means that:
2.7 = - log [OH]
[OH]- = 10^(2.7)
[OH]- = 501.187 M
Hope this helps :)