Question

If f(x)=1/6x+12, then f^-1(x)= PLEASE HELP

Answer 1

$f(x)=\dfrac{1}{6}x+12\to y=\dfrac{1}{6}x+12$

Change x to y, and y to x.

$x=\dfrac{1}{6}y+12$

solve for y:

$\dfrac{1}{6}y+12=x\ \ \ |-12\\\\\dfrac{1}{6}y=x-12\ \ \ \ |\cdot6\\\\y=6x-72$

Your answer is:

$f^{-1}(x)=6x-72$