Please help me how to do no 5

Mathematics

1 answer:

snow_tiger [21]4 years ago

3 0

Answer:

-864

Step-by-step explanation:

The determinant of a matrix product is the product of the determinants. The determinant of a transpose is the same as the determinant of the original. Hence ...

$|AB^5C^T|=(4)(-2)^5(\frac{1}{4})=-32$

The multiplication of an n×n matrix by a scalar 'a' multiplies its determinant by a^n, so the desired determinant is ...

$|3AB^5C^T|=3^3(-32) = \boxed{-864}$

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