Please help me please will give brainliest to anyone only do number 11
1 answer:
9514 1404 393
Answer:
9. ±1, ±2, ±3, ±6
11. ±1, ±2, ±3, ±4, ±6, ±12
Step-by-step explanation:
The possible rational roots are (plus or minus) the divisors of the constant term, divided by the divisors of the leading coefficient.
Here, the leading coefficient is 1 in each case, so the possible rational roots are plus or minus a divisor of the constant term.
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9. The constant is -6. Divisors of 6 are 1, 2, 3, 6. The possible rational roots are ...
±{1, 2, 3, 6}
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11. The constant is 12. Divisors of 12 are 1, 2, 3, 4, 6, 12. The possible rational roots are ...
±{1, 2, 3, 4, 6, 12}
_____
A graphing calculator is useful for seeing if any of these values actually are roots of the equation. (The 4th-degree equation will have 2 complex roots.)
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Let us add consecutive odd numbers and try to find any relationship.
1. 1
2. 1+3 = 4 ( square of 2 i.e )
3. 1+3+5 = 9 ( )
4. 1+3+5+7 = 16 ( )
5. 1+3+5+7+9 = 25 ( )
6. 1+3+5+7+9+11 = 36 ( )
7. 1+3+5+7+9+11+13 = 49 ( )
If we notice, the sum of the consecutive odd integers in each case is equal to the square of the place where it lies. For example, the sum of numbers in seventh place is equal to . The sum of the numbers in the fifth line is equal to
.