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Lesechka [4]
3 years ago
9

Please help me please will give brainliest to anyone only do number 11​

Mathematics
1 answer:
AnnZ [28]3 years ago
8 0

9514 1404 393

Answer:

  9.  ±1, ±2, ±3, ±6

  11.  ±1, ±2, ±3, ±4, ±6, ±12

Step-by-step explanation:

The possible rational roots are (plus or minus) the divisors of the constant term, divided by the divisors of the leading coefficient.

Here, the leading coefficient is 1 in each case, so the possible rational roots are plus or minus a divisor of the constant term.

__

9. The constant is -6. Divisors of 6 are 1, 2, 3, 6. The possible rational roots are ...

  ±{1, 2, 3, 6}

__

11. The constant is 12. Divisors of 12 are 1, 2, 3, 4, 6, 12. The possible rational roots are ...

  ±{1, 2, 3, 4, 6, 12}

_____

A graphing calculator is useful for seeing if any of these values actually are roots of the equation. (The 4th-degree equation will have 2 complex roots.)

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(This is assuming that S'mores would need 2 grahams, 1 marshmallow and 1 chocolate piece.)


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Let's take your problem into account and see what we have:

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