Answer:
The distance between A(-8, 4) and B(4, -1) is 13 units.
Step-by-step explanation:
To find the distance between any two points, we can use the distance formula given by:

We have the two points A(-8, 4) and B(4, -1). Let A(-8, 4) be (<em>x₁, y₁</em>) and let B(4, -1) be (<em>x₂, y₂</em>). Substitute:

Evaluate:

So:

The distance between A(-8, 4) and B(4, -1) is 13 units.
The distance between point on the ground from the top of the building is 396 meter, if the building is 280 m high and The angle of depression from the top of a building to a point on the ground is 45 degrees.
Step-by-step explanation:
The given is,
The angle of depression from the top of a building to a point on the ground is 45 degrees.
Height of the building is 280 meter.
Step: 1
Given diagram is a right angled diagram,
For right angle triangle,
90° = 45° + 45°
= 90°
Trignometric ratio,
sin ∅ =
....................(1)
For the above ratio take the bottom angle, that is angle of depression from the top of a building to a point on the ground is 45 degrees.
Where, Opp side = 280 meters
Hyp side = x
∅ = 45°
Equation (1) becomes,
sin 45° = 
0.70710678 = 
x = 
x = 395.979
Distance between point on the ground from the top of the building, x ≅ 396 meter
Trignometric ratio,
cos ∅ =
Cos 45 =
Adj = (0.70710678)(396)
Bottom length, Adj = 280 meter
Result:
The distance between point on the ground from the top of the building is 396 meter.
The answer is A. 3.19, all you have to do it multiply 3.19x5 then add the 2.95 hope this helps
Answer:
$45 with 20% markup = $45 + $9 for a new total = $54
$7.60 with a 50% markup = $7.60 + $3.80 for new total = $11.40
Step-by-step explanation:
Answer: A. A=(1000-2w)*w B. 250 feet
C. 125 000 square feet
Step-by-step explanation:
The area of rectangular is A=l*w (1)
From another hand the length of the fence is 2*w+l=1000 (2)
L is not multiplied by 2, because the opposite side of the l is the barn,- we don't need in fence on that side.
Express l from (2):
l=1000-2w
Substitude l in (1) by 1000-2w
A=(1000-2w)*w (3) ( Part A. is done !)
Part B.
To find the width w (Wmax) that corresponds to max of area A we have to dind the roots of equation (1000-2w)w=0 ( we get it from (3))
w1=0 1000-2*w2=0
w2=500
Wmax= (w1+w2)/2=(0+500)/2=250 feet
The width that maximize area A is Wmax=250 feet
Part C. Using (3) and the value of Wmax=250 we can write the following:
A(Wmax)=250*(1000-2*250)=250*500=125 000 square feets