4 years ago

What is the center and radius of the circle with equation x2 + y2 - 4x + 22y + 61 = 0?

1 answer:

6 0

Hello,

$x^2+y^2-4x+22y+61=0\\\\
(x^2-4x+4) +(y^2+22y+121)-121-4+61=0\\\\
(x-2)^2+(y+11)^2=64


$

Center is (2,-11) and radius is 8

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