Question

What is the center and radius of the circle with equation x2 + y2 - 4x + 22y + 61 = 0?

Answer 1

Hello,

$x^2+y^2-4x+22y+61=0\\\\ (x^2-4x+4) +(y^2+22y+121)-121-4+61=0\\\\ (x-2)^2+(y+11)^2=64$

Center is (2,-11) and radius is 8