Question

How many solutions does this linear system have? y = y equals StartFraction 2 over 3 EndFraction x plus 2.x+ 2 6x – 4y = –10

Answer 1

Answer:

its c

Step-by-step explanation:

no solution

Answer 2

Answer:

The system has one solution

Step-by-step explanation:

we have the system of equations

$y=\frac{2}{3}x+2$ ----> equation A

$6x-4y=-10$ ----> equation B

Solve the system by substitution

substitute equation A in equation B

$6x-4(\frac{2}{3}x+2)=-10$

$6x-\frac{8}{3}x-8=-10$

Solve for x

Multiply by 3 both sides to remove the fraction

$18x-8x-24=-30$

Combine like terms

$10x=-30+24$

$10x=-6$

$x=-\frac{6}{10}$

Simplify

$x=-\frac{3}{5}$

Find the value of y

$y=\frac{2}{3}(-\frac{3}{5})+2$

$y=-\frac{6}{15}+2$

$y=\frac{24}{15}$

Simplify

$y=\frac{8}{5}$

The solution of the system is the point $(-\frac{3}{5},\frac{8}{5})$

therefore

The system has one solution