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Studentka2010 [4]

2 years ago

6

12- |-10| = how to simplify it?

2 answers:

maxonik [38]2 years ago

8 0

To get the answer for this problem you must know that anything inside | here | will become a positive regardless if it’s a negative.

To answer the problem you would make the -10 a positive, so now it’s 12-10 which equals 2.

adelina 88 [10]2 years ago

6 0

$12- |-10| = 12-10=2$

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2 years ago

There are 9 apples. there are 6 fewer apples than oranges. how many oranges are there

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3 years ago

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Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers

Alenkinab [10]

Given:

$\sigma_A=3$

$n_A=6$

$\sigma_B=5$

$n_B=4$

$\overline{x}_A=\overline{x}_B$

To find:

The variance. of combined set.

Solution:

Formula for variance is

$\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}$ ...(i)

Using (i), we get

$\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}$

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$54=\sum (x_i-\overline{x}_A)^2$

Similarly,

$\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}$

$(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$100=\sum (x_i-\overline{x}_B)^2$

Now, after combining both sets, we get

$\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}$

$\sigma^2=\dfrac{54+100}{6+4}$

$\sigma^2=\dfrac{154}{10}$

$\sigma^2=15.4$

Therefore, the variance of combined set is 15.4.

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2 years ago

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2 years ago

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Firdavs [7]

I hope this helps you

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x=1/5

3 0

2 years ago