X^2 - x - 20
(x + 4)(x - 5) <==
x^2 - x - 20.....the last sign, which is negative, tells me that one set is positive and one set is negative. The first sign, which is also negative, tells me that the larger number will be negative. Now u have to find 2 numbers, that when added equal -1 and when multiplied, equal -20....those numbers are -5 and 4. so ur answer is : (x + 4)(x - 5)
Subtract 12 from both sides
4(2x + 2) > 100 - 12
Simplify 100 - 12 to 88
4(2x + 2) > 88
Divide both sides by 4
2x + 2 > 88/4
Simplify 88/4 to 22
2x + 2 > 22
Subtract 2 from both sides
2x > 22 - 2
Simplify 22 - 2 to 20
2x > 20
Divide both sides by 2
x > 20/2
Simplify 20/2 to 10
<u>x > 10</u>
Answer: (-9, -3)
Step-by-step explanation:
A = (-3, -1)
A' = (-3, -1)*3 = (-9, -3)
Well plug 0 in for x and solve for y and that is the vertex of your expression
Answer:
<h3>The answer is option C</h3>
Step-by-step explanation:
Since it's a right angled triangle we can use trigonometric ratios to find the value of ∠Y
To find the value of ∠Y we use tan
We have
We have the final answer as
<h3>51.34°</h3>
Hope this helps you
