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3 years ago

Find the value of y for a given value of x, if y varies directly with x

1 answer:

6 0

It is said that y varies directly to x which can be written as follows:

y = kx

where k is the constant of proportionality.

To be able to solve the problem, we need to determine the value of k. We do as follows:

y = kx
-252 = k(84)
k = -3

y = -3x
y = -3(74)
y = -222

Hope this helps. Have a nice day.

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Joseph is creating a dilation through point B with a scale factor of 2. Which statements about the dilation are correct? Check a

swat32

Answer:

Options (1), (2) and (4).

Step-by-step explanation:

Given question is incomplete; Find the complete question in the attachment.

Triangle ABC is a right triangle.

ΔABC has been dilated by a scale factor of 2 forming ΔA'B'C'.

These are the observations,

1). A and A' will be co-linear.

2). Since the given triangle has been dilated about a point B therefore, after dilation vertex B and B' will at be same location.

3). Length of B'C' = 2BC

4). AB and BC are the segments which will lie on the sides BA' and BC'.

5). Pre-image ABC will be inside the image A'B'C'.

Therefore, Options (1), (2) and (4) will be the answer.

4 0

3 years ago

Read 2 more answers

What number must be added to 15,-6, and 12 to have a mean of 5? Explain.

Genrish500 [490]

You need to add a -1

We can find this by setting up the equation like so

x + (-6) + 12 + 15 / 4 = 5

x + 21 = 20

x = 20 -21

x = -1

Now if we insert -1 where x is located in the equation, you will get a means of 5

3 0

3 years ago

1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING

iogann1982 [59]

$y=\displaystyle\sum_{n=0}^\infty a_nx^n$

then

$y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n$

The ODE in terms of these series is

$\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0$

$\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0$

$\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}$

We can solve the recurrence exactly by substitution:

$a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0$

$\implies a_n=\dfrac{(-2)^n}{n!}a_0$

So the ODE has solution

$y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}$

which you may recognize as the power series of the exponential function. Then

$\boxed{y(x)=a_0e^{-2x}}$

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3 years ago

In the circle below, EG is a diameter and EF is tangent at E. Suppose mEF = 124°. Find the following. Does anyone know this?

Ludmilka [50]

Answer:

Step-by-step explanation:

If EG is a diameter, then arc EFG is a semicircle and its measure is 180. Arc FG then is 180 - 124 = 56. Since angle FEG is an inscribed angle and the arc it cuts off is arc FG, then the measure of the inscribed angle is half the measure of the arc it cuts off...so angle FEG is 28 degrees. Keep that in mind; we'll need it in a sec.

If HE is tangent to the circle at E, then angle HEG is a 90 degree angle. Adding that to angle FEG will give you angle FEH. Angle FEH = 90 + 28 = 118

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3 years ago

Find the exact value of sec 795

sladkih [1.3K]

Evaluate the trigonometric expression using sum and difference formulas.

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3 years ago

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