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solmaris [256]
3 years ago
14

Find the value of y for a given value of x, if y varies directly with x

Mathematics
1 answer:
Sophie [7]3 years ago
6 0
It is said that y varies directly to x which can be written as follows:

y = kx

where k is the constant of proportionality. 

To be able to solve the problem, we need to determine the value of k. We do as follows:

y = kx
-252 = k(84)
k = -3

y = -3x
y = -3(74)
y = -222

Hope this helps. Have a nice day.
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Answer:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

Step-by-step explanation:

x^{2}+6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

x^{2}+6x+9-9-5=0

we have:

(x+3)^{2}-9-5=0

(x+3)^{2} = 14

lets apply square root on both sides of the equation:

\sqrt{(x+3)^{2}}=\sqrt{14}

we know:

\sqrt{a^{2}} = abs(a)

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abs(x+3)=\sqrt{14}

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finally we have:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

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Step-by-step explanation:

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