All categories

3 years ago

To find the sum or total of two numbers, we ? ( add, subtract,multiply,divide)

2 answers:

8 0

You add , subtract,multiply and divide to find the total but you only add to find the sum so the correct answer would be add
Hope this helped

tigry1 [53]3 years ago

7 0

You would add the two numbers together

You might be interested in

Katie and jennifer are playing a game. katie and jennifer each started with 100 points. at the end of each turn katies points do

ella [17]

It is the fourth round and this is because in round one Katie has 200 and Jenny will have 300.In round two katie will have 400 and Jennifer will have 500.In round 3 Katie will have 600 and and jennifer will have 800.I

3 0

3 years ago

Solve for h. <br> 7/5h - 2= -3/5h +7<br> Please show work!

netineya [11]

7/5h+3/5h-2=7
10/5h-2=7
2h=11
h=5.5

3 0

3 years ago

Read 2 more answers

find the slope between each pair of points please help with these three questions and i’ll mark the brain thing !

madam [21]

(If It's a number like this: 8/9 then it's a fraction)

Answer:

Step-by-step explanation:

Yay, I love doing these!

9.} 6 - 8 and 4- -2= -2/6

10.} 3 - 9 and -1 - 9= -6/-10

11.} -1 - -7 and 5 - -3= 6/8 simplify it by 2= 3/4

5 0

3 years ago

Let X and Y be discrete random variables. Let E[X] and var[X] be the expected value and variance, respectively, of a random vari

Ulleksa [173]

Answer:

(a) $E[X+Y]=E[X]+E[Y]$

(b) $Var(X+Y)=Var(X)+Var(Y)$

Step-by-step explanation:

Let X and Y be discrete random variables and E(X) and Var(X) are the Expected Values and Variance of X respectively.

(a)We want to show that E[X + Y ] = E[X] + E[Y ].

When we have two random variables instead of one, we consider their joint distribution function.

For a function f(X,Y) of discrete variables X and Y, we can define

$E[f(X,Y)]=\sum_{x,y}f(x,y)\cdot P(X=x, Y=y).$

Since f(X,Y)=X+Y

$E[X+Y]=\sum_{x,y}(x+y)P(X=x,Y=y)\\=\sum_{x,y}xP(X=x,Y=y)+\sum_{x,y}yP(X=x,Y=y).$

Let us look at the first of these sums.

$\sum_{x,y}xP(X=x,Y=y)\\=\sum_{x}x\sum_{y}P(X=x,Y=y)\\\text{Taking Marginal distribution of x}\\=\sum_{x}xP(X=x)=E[X].$

Similarly,

$\sum_{x,y}yP(X=x,Y=y)\\=\sum_{y}y\sum_{x}P(X=x,Y=y)\\\text{Taking Marginal distribution of y}\\=\sum_{y}yP(Y=y)=E[Y].$

Combining these two gives the formula:

$\sum_{x,y}xP(X=x,Y=y)+\sum_{x,y}yP(X=x,Y=y) =E(X)+E(Y)$

Therefore:

$E[X+Y]=E[X]+E[Y] \text{ as required.}$

(b)We want to show that if X and Y are independent random variables, then:

$Var(X+Y)=Var(X)+Var(Y)$

By definition of Variance, we have that:

$Var(X+Y)=E(X+Y-E[X+Y]^2)$

$=E[(X-\mu_X +Y- \mu_Y)^2]\\=E[(X-\mu_X)^2 +(Y- \mu_Y)^2+2(X-\mu_X)(Y- \mu_Y)]\\$Since we have shown that expectation is linear$\\=E(X-\mu_X)^2 +E(Y- \mu_Y)^2+2E(X-\mu_X)(Y- \mu_Y)]\\=E[(X-E(X)]^2 +E[Y- E(Y)]^2+2Cov (X,Y)$

Since X and Y are independent, Cov(X,Y)=0

$=Var(X)+Var(Y)$

Therefore as required:

$Var(X+Y)=Var(X)+Var(Y)$

7 0

3 years ago

Enter the correct 9 letter sequence (no space) use all capital letters

olya-2409 [2.1K]

Answer:

i think you forgot the rest of the question?

6 0

3 years ago