Answer:
This would probely be 266.
Step-by-step explanation:
There are three kids so I would divide them by three. Or multiply 266 by three. Of course there would still be 2$ left.
Answer:
15.3feet
Step-by-step explanation:
Given the scale model of a train as;
2cm = 3feet
We are to find the height of real train of height 10.2cm, we can write;
10.2cm = x
Divide both expressions
2/10.2 = 3/x
2x = 3×10.2
2x = 30.6
x= 15.3
Hence the height if the real train is 15.3feet
∠ ABD = 5(2X+1)
∠ DBC = 3X+6
∠ EBC = Y +135/2
∠ ABD and ∠ DBC are linear pairs
∴ ∠ ABD +∠ DBC = 180
∴ 5(2X+1) + 3X+6 =180
solve for x
∴ x = 13
∴∠ ABD = 5(2X+1) = 5(2*13+1) = 135
∠ DBC = 3x+6 = 3*13+6 = 45
∠ ABD and ∠ EBC are vertical angles
∴ ∠ ABD = ∠ EBC = 135
∴ y +135/2 = 135
∴ y = 135/2
The <span>statements that are true:
--------------------------------------</span><span>
C.) x=13
E.)measure of angle EBC =135
F.) angle DBC and angle EBC are linear pairs
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