Answer:
C=y=sin1/2x
Step-by-step explanation:
As given in the graph:
Amplitude= 1
period=2π
Finding function of sin that have period of 4π and amplitude 1
A: y=1/2sinx
Using the formula asin(bx-c)+d to find the amplitude and period
a=1/2
b=1
c=0
d=0
Amplitude=|a|
=1/2
Period= 2π/b
=2π
B: y=sin2x
Using the formula asin(bx-c)+d to find the amplitude and period
a=1
b=2
c=0
d=0
Amplitude=|a|
=1
Period= 2π/2
=π
C: y=sin1/2x
Using the formula asin(bx-c)+d to find the amplitude and period
a=1
b=1/2
c=0
d=0
Amplitude=|a|
=1
Period= 2π/1/2
=4π
D: y=sin1/4x
Using the formula asin(bx-c)+d to find the amplitude and period
a=1
b=1/4
c=0
d=0
Amplitude=|a|
=1
Period= 2π/1/4
=8π
Hence only c: y=sin1/2x has period of 2π and amplitude 1
Answer:
12 units
Step-by-step explanation:
To find any side length of a right triangle given two side lengths, you would use the pythagorean theorem which is a² + b² = c². In this equation, a and b represents either the height of base of the triangle, and c represents the hypotenuse of the triangle (the diagonal line - in your question it is 13). By plugging in the base and hypotenuse, you get the equation of 5² + b² = 13². 5² is equal to 25 and 13² is equal to 169, so the equation is 25 + b² = 169. Subtract 25 for both sides of the equation and you find that b² = 144. Square both sides and the missing length is 12 because √144 = 12.
Answer:
y=13.15x+14
Step-by-step explanation:
That is the equation, if you need the graph lmk
Answer:
x = 11
Step-by-step explanation:
33 divided by 3 is 11, and 11 times 3 is 33.
Answer:
The answer is 20
Step-by-step explanation:
From the graph it shows that J is located at point 15, and Q is located at point 35
If we move 20 units from point J to point Q, we land at point Q, making it the distance they are from one another.
