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Delicious77 [7]
3 years ago
15

Eli, Freda and Geoff were given ?800 to share in the ratio of their ages. Eli is 9 years old,Feda is 13 years old and Geoff is 1

8 years old. How much should they each get? Eli- Freda- Geoff-
Mathematics
2 answers:
vodomira [7]3 years ago
6 0

Answer:

This would probely be 266.

Step-by-step explanation:

There are three kids so I would divide them by three. Or multiply 266 by three. Of course there would still be 2$ left.

aleksandrvk [35]3 years ago
3 0

Answer:

Share of Eli, Freda and Geoff will be $180, $260, $360 respectively.

Step-by-step explanation:

Eli, Freda and Geoff were given $800 to share in the ratio of their age.

Their ages were 9 years, 13 years and 18 years respectively.

Ratio of their ages will be 9 : 13 : 18

Now share of Eli will be = \frac{9}{9+13+18}\times 800

= \frac{9\times 800}{40}

= $180

Share of Freda will be = \frac{13}{9+13+18}\times 800

                                     = $260

Share of Geoff will be = \frac{18}{9+13+18}\times 800

                                     = $360

Therefore, share of Eli, Freda and Geoff will be $180, $260, $360 respectively.

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A total of 800 pre-sale tickets and tickets at the gate were sold to football city championship game. If the number of tickets s
Nitella [24]

The number of presale tickets sold is 271

<em><u>Solution:</u></em>

Let "p" be the number of presale tickets sold

Let "g" be the number of tickets sold at gate

<em><u>Given that, total of 800 Pre-sale tickets and tickets at the gate were sold</u></em>

Therefore,

Presale tickets + tickets sold at gate = 800

p + g = 800 ------ eqn 1

<em><u>Given that, number of tickets sold at the gate was thirteen less than twice the number of pre-sale tickets</u></em>

Therefore,

Number of tickets sold at gate = twice the number of pre-sale tickets - 13

g = 2p - 13 ------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Substitute eqn 2 in eqn 1

p + 2p - 13 = 800

3p -13 = 800

3p = 800 + 13

3p = 813

p = 271

Thus 271 presale tickets were sold

4 0
3 years ago
If mBAC = 25°, then mCAD = ?
Anit [1.1K]
It would also be 25 degrees
8 0
3 years ago
Please help!<br> "Congruence and Constructions".
marin [14]

Answer:

MNK = TRP

MN is congruent to TR.

X = 6.3

Step-by-step explanation:

MNK is congruent to TRP because the two triangles are congruent, which is a given statement. This also means that all side and angle measures will be congruent. Because of this, it can be inferred that MN is congruent to TR and they have equal side length measures. This means that TR measures 20. This means that 3X - 1 = 20. By solving we can get 6.33.

7 0
3 years ago
Which three lengths could be the lengths
Fed [463]

Given:

The three lengths in the options.

To find:

Which three lengths could be the lengths of the sides of a triangle?

Solution:

If the sum of two smaller sides is greater than the largest side, then the three sides can form a triangle otherwise the triangle is not possible.

In option A, the three sides are 4 cm, 8 cm, 13 cm. Here, the largest side is 13 cm.

Sum of two smaller sides is:

4+8=12

4+8

So, the triangle is not possible.

In option B, the three sides are 13 cm, 11 cm, 23 cm. Here, the largest side is 23 cm.

Sum of two smaller sides is:

13+11=24

13+11>23

So, the triangle is possible.

In option C, the three sides are 5 cm, 18 cm, 12 cm. Here, the largest side is 18 cm.

Sum of two smaller sides is:

5+12=17

5+12

So, the triangle is not possible.

In option D, the three sides are 25 cm, 8 cm, 16 cm. Here, the largest side is 25 cm.

Sum of two smaller sides is:

8+16=24

8+16

So, the triangle is not possible.

Therefore, the correct option is B. The three lengths 13 cm, 11 cm, 23 cm could be the lengths of the sides of a triangle.

6 0
3 years ago
Mr. Wilson is giving his students a vocabulary test tomorrow over all the terms they have learned from this semester. Today, he
Y_Kistochka [10]
The population in the above situation is the total number of students under Mr. Wilson.

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5 0
3 years ago
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