For this, we will be using the quadratic formula, which is
, with a=x^2 coefficient, b=x coefficient, and c = constant. Our equation will look like this: 
Firstly, solve the multiplications and the exponents: 
Next, do the addition: 
Next, your equation will be split into two:
. Solve them separately, and your answer will be
Complete question is;
Building an A - frame dog house. Your club has decided to build and sell dog houses for a fundraising project. You found this dog house a set of plans by searching the net.
side 1 = 45¼ in
side 2 = (Gusset plate)
5¾ in high
3⅓ in base
corner of side 2 = 2 inches thick
side 3 (floor plate)= 37¼ in
A customer has offered to pay extra if you will make one half the size called for in the plans. Take each of the 5 measures shown in the drawing and find half of the measure. Show your work to get full credit!
Answer:
new side 1 = 22⅝ in
For side 2:
New height = 2⅞
New base = 1⅔ in
New corner = 1 in
New side 3 = 18⅝ in
Step-by-step explanation:
We are told that a customer has offered to pay extra if you will make one half the size called for in the plans.
Thus, we will divide each number by 2
We are given side 1 = 45 1/4 in = 45.25 in
New side 1 = 45.25/2 = 22.625
Converting to fraction form: new side 1 = 22⅝ in
We are given side 2 = (Gusset plate)
Height = 5¾ in = 5.75 in
New height = 5.75/2 = =2.875
Converting to fraction:
New height = 2⅞
Base = 3⅓ in = 3.33 in
New base = 3.33/2 = 1.66
Converting to fraction:
New base = 1⅔ in
Corner of side 2 is 2 inches thick
New corner = 2/2 = 1 in
side 3 (floor plate) = 37¼ in = 37.25 in
New side 3 = 37.25/2 = 18.625
Converting to fraction:
New side 3 = 18⅝ in
Answer:
The correct choice is B
Step-by-step explanation:
The composite function (f o g)(x) is evaluated by substituting g(x) in place of x in f(x) which yields;
(f o g)(x) = (g(x))^3 which finally becomes; (1-5x^2)^3.
The domain of a function is defined as the set of x- values for which the function is real and defined. This function clearly is not a rational function and as such it has no undefined points nor domain constraints. It is defined and real for every value of x on the real line.
X² + 4x - 8 = 5
This is a simple quadratic equation. Let's move everything to the left side to start:
x² + 4x - 8 - 5 = 5 - 5
Now we have:
x² + 4x - 13 = 0
In a quadratic equation, x =

Therefore, we plug in a = 1, b = 4, and c = -13, and we find that x = -2 - sqrt{17} OR -2 + sqrt{17}.