Answer:
20 | 30
Step-by-step explanation:
Multiply 2/5 by 50 to find the tickets for children
2*50/5
= 100/5
= 20
To find the tickets sold for the other party we subtract 20 from 50
50 - 20
= 30
Answer:
<h2><u>
18%</u></h2>
Step-by-step explanation:
To do this, we first divide 2.87 by 3.50. This gets us 0.82. So we now know that 2.87 is 82% of 3.50. But we're trying to find the reduced amount. So we now Do 100%-82% (82% being 2.87) to get 18%. So the answer is 18%. To make sure we are right, we do 18% of 3.50 to get 0.63 cents. We then take 3.50 and subtract 0.63 to get 2.87. So it reduced by 18%
Hey there! I'm happy to help!
The Greatest Common Factor is self-explanatory: it is the largest factor that both numbers have in common. Let's look at the factors of each of these numbers:
30: 1, 30, 2, 15, 3, 10, 5, 6
45: 1, 45, 3, 15, 5, 9
We see that the largest number they both have in common is 15, so the GCF is 15.
Have a wonderful day! :D
Answer:
$45000
Step-by-step explanation:
Given data
Net income =$50,400
Let the prior year income be x
12/100*x +x= 50400
0.12x+x= 50400
1.12x= 50400
x= 50400/1.12
x= $45000
Hence the prior year income is $45000
Just like the previous one
if the ship travelled a total of 149 miles, then let's say it travelled East "d" miles and thus it travelled North the slack of 149 and "d", thus " 149 - d".
now, if the rate travelling East is say "r", then the faster rate going North is " r + 3".
![\bf \begin{array}{lccclll} &distance&rate&time\\ &-----&-----&-----\\ East&d&r&4\\ North&149-d&r+3&3 \end{array} \\\\\\ \begin{cases} \boxed{d}=4r\\ 149-d=(r+3)3\\ ----------\\ 149-\boxed{4r}=3(r+3) \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blccclll%7D%0A%26distance%26rate%26time%5C%5C%0A%26-----%26-----%26-----%5C%5C%0AEast%26d%26r%264%5C%5C%0ANorth%26149-d%26r%2B3%263%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Cbegin%7Bcases%7D%0A%5Cboxed%7Bd%7D%3D4r%5C%5C%0A149-d%3D%28r%2B3%293%5C%5C%0A----------%5C%5C%0A149-%5Cboxed%7B4r%7D%3D3%28r%2B3%29%0A%5Cend%7Bcases%7D)
solve for "r".