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viva [34]
4 years ago
7

A part of a line with endpoints on both ends is a(n):

Mathematics
1 answer:
patriot [66]3 years ago
4 0

I believe it's a segment.

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|6t−7|−8 ≥ 3 Please help me quick
Phantasy [73]
Hope the answer helps you!!!
:)

5 0
3 years ago
I have yet to understand this subject
Oliga [24]

the answer is -3/2 and -11/2

5 0
3 years ago
A line has a slope of zero and passes through the point (-2, 3). Which of the following points must also lie on the line?
brilliants [131]

Answer:

(5,3)

Step-by-step explanation

Because the slope is 0, it means its a horizontal line. because the horizontal is on 3, then it doesnt  matter what x is as long as y is 3 if that makes any sense.

7 0
3 years ago
PLZ HELP! 20 POINTS!!
ivann1987 [24]
Given list of values
A = {23, 34, 19, 10, 9, 20, 40, 43, 28, 29, 36, 13, 27, 23, 36, 37, 7}

Sort list A to get list B
B = {7, 9, 10, 13, 19, 20, 23, 23, 27, 28, 29, 34, 36, 36, 37, 40, 43}

The smallest value is 7, so the min is 7
The largest value is 43, so the max is 43

Look through list B to find the middle-most value. What you can do is cross off each pair of outer values (see figure 1 in the attached images) until you are left with the middle value
Or you can note how there are 17 values so the median is at slot 9 (there are 8 values below the median; 8 values above the median; the 8 is from 17/2 = 8.5)

Once you know the median is 27, we split the list B into two parts
The first part, we'll call it L for lower half is
L = {7, 9, 10, 13, 19, 20, 23, 23}
which is the list of all values lower or smaller than the median.
The median of list L is 16 because its the midway point between 13 and 19. We can compute (13+19)/2 = 32/2 = 16. This is the value of Q1

The upper half U is
U = {28, 29, 34, 36, 36, 37, 40, 43}
this list shows all the values larger than the median.
The value of Q3 is 36. We find the midpoint of 36 and 36 which is just 36.
The value of Q3 is the same as the median of list U

------------------------------------------------

Five Number Summary:
Min = 7
Q1 = 16
Median = 27
Q3 = 36
Max = 43

This five number summary is then used to construct the box-and-whisker plot. See figure 2 in the attached images. The diagram shows how each piece of the boxplot is put together (eg: the left edge of the box is the value of Q1). 

5 0
3 years ago
At what value of x does the graph of the following function F(x) have a
tankabanditka [31]

Given:

The function is

F(x)=\dfrac{1}{x+2}

To find:

The vertical asymptote of the given function.

Solution:

Vertical asymptote are the vertical line passes thought the values for which the function is not defined.

To find the vertical asymptote, equate the denominator equal to 0.

We have,

F(x)=\dfrac{1}{x+2}

Denominator is (x+2).

x+2=0

x=-2

The vertical asymptote is x=-2.

Therefore, the correct option is B.

8 0
2 years ago
Read 2 more answers
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