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Vesna [10]
3 years ago
8

According to recent UN figures, the annual gun homicide rate is 62.4 per one million residents in the US and 1.3 per one million

residents in Britain. Compare the proportion of residents killed annually by guns using the (a) difference of proportions, (b) relative risk. Which measure is more useful for describing the strength of association
Mathematics
1 answer:
ss7ja [257]3 years ago
3 0

Answer:

P_D=61.1*10^{-4}

R_r=480

Step-by-step explanation:

From the question we are told that

Homicide rate in US R_U=62.4\ per\ one\ million

Homicide rate in Britain R_B=1.3\ per\ one\ million

Generally the equation for probability of homicide is mathematically given as

P=\frac{R}{10^6}

Generally the equation for probability of homicide in US is mathematically given as

P_U=\frac{62.4}{10^6}

P_U=62.4*10^{-4}

Generally the equation for probability of homicide in Britain is mathematically given as

P_B=\frac{1.3}{10^6}

P_B=1.3*10^{-5}

a)Generally the difference b/w the probabilities P_D is mathematically given as

P_D=P_U-P_B

P_D=62.4*10^{-4}-1.3*10^{-5}

P_D=61.1*10^{-4}

Therefore US annual homicide is P_D=61.1*10^{-4} greater than Britain's

b)Generally the Relative risk is R_r is mathematically given as

R_r=\frac{P_U}{P_B}

R_r=\frac{62.4*10^{-4}}{1.3*10^{-5}}

R_r=480

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