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3 years ago

How do I simplify this problem?

Mathematics

1 answer:

masya89 [10]3 years ago

6 0

Expanding (x+h)^3, we get (5x^3+15x^2h+15xh^2+5h^3-5x^3)/h=
(15x^2h+15xh^2+5h^3)/h= 15x^2+15xh+h^2

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ernie walks 1/6 mile in 1/12 hour when he walks along the river trail. How many miles per hour does Ernie walk when he hikes on

ohaa [14]

Answer:

2 miles

Step-by-step explanation:

distance=rate*time

d=rt

1/6=r*(1/12)

multiply both sides by 12

12(1/6)=r*(1/12)12

2=r*1

2=r

rate=2 miles per hour

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3 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

iragen [17]

Answer:

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3 years ago

Lilium Inc., an automobile company, estimates a total factory overhead cost of $1,500,000 for the year and an activity base of 2

Jobisdone [24]

Answer:

The applied factory overhead cost is $1,875,000

Step-by-step explanation:

Overhead cost = $1,500,000 at activity base of 200,000

We assume that the overhead is directly proportional to the activity base;

The cost per direct labor = $1,500,000/200,000 = $7.5

Therefore at actual labor hours of 250,000, the factory overhead cost is therefore = $7.5 × 250000 = $1,875,000.

3 0

3 years ago

A circle is growing so that the radius is increasing at the rate of 3 cm/min. How fast is the area of the circle changing at the

Naya [18.7K]

Answer:

The area is growing at a rate of $\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}$

Step-by-step explanation:

<em>Notice that this problem requires the use of implicit differentiation in related rates (some some calculus concepts to be understood), and not all middle school students cover such.</em>

We identify that the info given on the increasing rate of the circle's radius is 3 $\frac{cm}{min}$ and we identify such as the following differential rate:

$\frac{dr}{dt} = 3\,\frac{cm}{min}$

Our unknown is the rate at which the area (A) of the circle is growing under these circumstances,that is, we need to find $\frac{dA}{dt}$ .

So we look into a formula for the area (A) of a circle in terms of its radius (r), so as to have a way of connecting both quantities (A and r):

$A=\pi\,r^2$

We now apply the derivative operator with respect to time ( $\frac{d}{dt}$ ) to this equation, and use chain rule as we find the quadratic form of the radius:

$\frac{d}{dt} [A=\pi\,r^2]\\\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}$

Now we replace the known values of the rate at which the radius is growing ( $\frac{dr}{dt} = 3\,\frac{cm}{min}$ ), and also the value of the radius (r = 12 cm) at which we need to find he specific rate of change for the area :

$\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}\\\frac{dA}{dt} =\pi\,*2*(12\,cm)*(3\,\frac{cm}{min}) \\\frac{dA}{dt} =226.19467 \,\frac{cm^2}{min}\\$

which we can round to one decimal place as:

$\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}$

4 0

3 years ago

Someone help, AA, SAS, SSS NOT SIMILAR?!!!

sineoko [7]

Answer:

answer is AA criteria

hope it helps.

3 0

3 years ago

Read 2 more answers