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3 years ago

How do I simplify this problem?

Mathematics

1 answer:

masya89 [10]3 years ago

6 0

Expanding (x+h)^3, we get (5x^3+15x^2h+15xh^2+5h^3-5x^3)/h=
(15x^2h+15xh^2+5h^3)/h= 15x^2+15xh+h^2

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After 60 minutes a train has moved 60 miles toward its destination.

Fantom [35]

Answer:

1 mile per minute

Step-by-step explanation:

3 0

2 years ago

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#11 i

Paraphin [41]

The area of a shape is the amount of space a shape can occupy, while the perimeter is the sum of its lengths.

The perimeter is $18 + 3\sqrt 5 + 3\sqrt 2$ units
The area of the sanctuary is 27 square units

We have:

$A = (5,7)\\B=(8, 7)\\C=(8, 1)\\D=( 1, 1)\\E=( 1, 4)\\F= ( 5,4)$

Perimeter

See attachment for the layout of the sanctuary

$BC = \sqrt{(8 - 8)^2 + (7 - 1)^2} = 6$

$EF = \sqrt{(1 - 5)^2 + (4 - 4)^2} = 4$

$FA = \sqrt{(5 - 5)^2 + (4 - 7)^2} = 3$

From the attachment, the sides are

AB, BF, FC, CD, DE and EA

Start by calculating the length of each side using the following distance formula:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_2)^2}$

So, we have:

$AB = \sqrt{(5 - 8)^2 + (7 - 7)^2} = 3$

$BF = \sqrt{(8 - 5)^2 + (7 -1)^2} = \sqrt{45} = 3\sqrt 5$

$FC = \sqrt{(8 - 5)^2 + (1 -4)^2} = \sqrt{18} = 3\sqrt 2$

$CD = \sqrt{(8 - 1)^2 + (1 - 1)^2} = 7$

$DE = \sqrt{(1 - 1)^2 + (1 - 4)^2} = 3$

$EA = \sqrt{(1 - 5)^2 + (4 -7)^2} = 5$

So, the perimeter (P) is:

$P = AB + BF + FC + CD + DE + EA$

$P = 3 + 3\sqrt 5 + 3\sqrt 2 + 7 + 3 + 5$

$P = 18 + 3\sqrt 5 + 3\sqrt 2$

Hence, the perimeter is $18 + 3\sqrt 5 + 3\sqrt 2$ units

Area

To calculate the area, we need to divide the sanctuary into three.

Triangle ABF
Triangle EFA
Trapezium CDEF

The area of ABF is:

$Area = \frac 12 \times AB \times FA$

Where:

$AB = 3$

$FA = \sqrt{(5 - 5)^2 + (4 - 7)^2} = 3$

$Area = \frac 12 \times 3 \times 3$

$Area = \frac 92$

The area of EFA is:

$Area = \frac 12 \times EF \times FA$

Where:

$FA = 3$

$EF = \sqrt{(1 - 5)^2 + (4 - 4)^2} = 4$

So:

$Area = \frac 12 \times 4 \times 3$

$Area = 6$

The area of CDEF is:

$Area = \frac 12(CD + EF) \times DE$

Where

$CD = 7$

$EF = 4$

$DE = 3$

So, we have:

$Area = \frac 12 (7 + 4) \times 3$

$Area = \frac 12 \times 11 \times 3$

$Area = \frac {33}2$

So, the area of the sanctuary is:

$Area = \frac 92 + 6 + \frac {33}2$

$Area = \frac {9 +12 + 33}2$

$Area = \frac {54}2$

$Area = 27$

Hence, the area of the sanctuary is 27 square units

Read more about areas and perimeters at:

brainly.com/question/11957651

8 0

3 years ago

horrorfan [7]

Answer:

Step-by-step explanation:

they are both written about a particular individals life

4 0

3 years ago

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How do i make (9x-7y=-7) into slope intercept form?

ahrayia [7]

It's called "solve the equation for 'y' ". That means move things
around so that you end up with 'y' all alone on one side, and
everything else on the other side.

You started with 9x - 7y = -7

Subtract 9x from each side: - 7y = -9x - 7

Divide each side by -7 : y = 9/7 x + 1

6 0

3 years ago

A high school drama club is putting on their annual theater production. There is a maximum of 800 tickets for the show. The cost

astra-53 [7]

a.) Let x be the number of tickets sold before the event and y the number of tickets sold on the day of the event. Then x + y =< 800 and 6x + 9y >= 5000. (b.) Suppose the club sold 440 tickets before the event, i.e. x = 440, maximum number of tickets remaining to be sold = 800 - 440 = 360. Maximum amount realized from the sales supposing all tickets were sold = 6(440) + 9(360) = 2640 + 3240 = $5880 which is greater than $5000. Therefore, it is possible for the club to sell enough additional tickets on the day of the show to meet the expenses of the show.

3 0

2 years ago