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In-s [12.5K]
3 years ago
13

Contain (5,0) and (9,4)

Mathematics
1 answer:
algol [13]3 years ago
5 0

I will assume you would like the line

slope = (y2-y1)/ (x2-x1)

    m = (4-0)/(9-5)  = 4/4 = 1

equation of a line in point slope form is

y-y1 = m (x-x1)

y-0 = 1 (x-5)

y=x-5

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3/(30×30×30) = 3/27000 = 0.0001 or 0.01%

Step-by-step explanation:

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Kelly contracts with Raphael for Raphael to bring a pony to her daughter's birthday party in exchange for $100. Kelly later lear
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It was discharged by substituted contract

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3 years ago
If two angles are both vertical and supplementary, can we determine the angles? Is it possible to be both vertical and complemen
Mars2501 [29]

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Step-by-step explanation:

6 0
3 years ago
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EXPLAIN IT WORD FOR WORD ON HOW TO SOLVE IT
eimsori [14]
To start, first add up the total number of reservations made this week which would be adding up the total amount of reservations for each day:
15+5+10+25+40+30+35= 160
Then, since it is asking for the percent of Friday and Saturday, add the amounts together (40+30) which is 70. 
Then, set these as a fraction where it is the reservations for Friday and Saturday over the total amount of reservations: 70/160
Now that you got that, do 70 divided by 160 which is 0.4375.
Finally, convert 0.4375 to a percent by moving the decimal right two and you get 43.75% as your answer.

5 0
3 years ago
Assume line q is parallel to line m. Choose from the drop-down menus to solve for m∠6:
egoroff_w [7]

1st part: you do 180 - 110 = 70

Why you subtract 180 from 110 is linear adds up to 180, so 70 + 110 would get 180 if that makes sense.

2nd part: 180 - 115 = 65

This is similar concept to what I explained with the first part.

3rd part: Triangle sum theorem is 180

4th part: To get angle 7 I believe you just subtract

180 - 70 - 65 = 45

5th part: 7 and 6 I believe are vertical angles and vertical angles are congruent which would make 6 = 7

6 would also = 45

Although I cannot see the options for each of the question(s) choices, I hope this can help you. :)

4 0
2 years ago
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