since this is a multiplication, all the numerators are just factors of the product numerator and all denominators are just factors of the product denominator, so we can simply reorder them some, without changing the product.
Let's see
In ∆ABE and ∆CBE
- BE=BE(Common side)
- AE=EC[Diagonals of a parallelogram bisect each other]
- <AEB=<BEC[90°]
So by
SAS congruence the triangles are congruent
AB=BC
Fact:-
It's already given AC is perpendicular to BD
- It means diagonals are perpendicular to each other
According to general property of rhombus this parallelogram is also a rhombus.
So sides are equal hence AB =BC
44
Assuming JM and LN are parallel, KMJ=MKN. MKN is part of a triangle where the other two values are defined (48 and 88). By subtracting these values from 180, we find the value of MKN is 44, which therefore is also the value of KMJ.
10 I think..I might be wrong
