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Sloan [31]
3 years ago
6

3) Write the operation used to obtain the types of solutions.

Mathematics
2 answers:
never [62]3 years ago
8 0
Sum is the correct operation.
Alex Ar [27]3 years ago
5 0

Answer:

the Sum

hope this helps

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You draw two cards from a standard deck of 52 cards. What is the probability of drawing a club and then a diamond consecutively
otez555 [7]

Answer:

There are 13 cards for each suit so the first fraction is 13/52 and the next one is 13/51 as there is no replacement for the first card you pulled.

Multiplying them you get: 13/52*13/51= 169/2652,

Then you divide both sides by 13 to get: 13/204

So, the answer is C.

I hope this helps!

5 0
3 years ago
Read 2 more answers
Please help with this. 13 points and brainly PLEASE
Katyanochek1 [597]

Answer:

100 im pretty sure because 10 x 10 = 100

7 0
3 years ago
Devin used what he learned in clas to determine that for every 8 grams of oxygen in water, there is 1 gram of hydrogen
MAXImum [283]
And?... is that the question or is there more?
6 0
3 years ago
on a lake, Carol rowed a boat for 1/8 mile. Then luke rowed the boat for 3/8 mile. how far did carol and like row in all? simpli
Semmy [17]

Answer:

Total = \frac{1}{2}

Step-by-step explanation:

Given

Carol = \frac{1}{8}

Luke = \frac{3}{8}

Required

How far did they row together

To do this, we simply add the distance they both covered.

Total = Carol + Luke

This gives;

Total = \frac{1}{8} + \frac{3}{8}

Take LCM

Total = \frac{1+3}{8}

Total = \frac{4}{8}

Simplify

Total = \frac{1}{2}

<em>Hence, they both rowed 1/2 mile</em>

7 0
3 years ago
What are the solutions of the equation x^4 + 6x^2 + 5 = 0? Use u substitution to solve.
Radda [10]

Answer:

second option

Step-by-step explanation:

Given

x^{4} + 6x² + 5 = 0

let u = x², then

u² + 6u + 5 = 0 ← in standard form

(u + 1)(u + 5) = 0 ← in factored form

Equate each factor to zero and solve for u

u + 1 = 0 ⇒ u = - 1

u + 5 = 0 ⇒ u = - 5

Change u back into terms of x, that is

x² = - 1 ( take the square root of both sides )

x = ± \sqrt{-1} = ± i ( noting that \sqrt{-1} = i ), and

x² = - 5 ( take the square root of both sides )

x = ± \sqrt{-5} = ± \sqrt{5(-1)} = ± \sqrt{5} × \sqrt{-1} = ± i\sqrt{5}

Solutions are x = ± i and x = ± i\sqrt{5}

3 0
3 years ago
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