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3 years ago

Which expression is equivalent to 5^10•5^5?

Mathematics

2 answers:

Digiron [165]3 years ago

6 0

Answer:

5^15

Step-by-step explanation:

You add the exponents

Tju [1.3M]3 years ago

4 0

When we have exponents multiplied with the same base we add them so 5^5*5^10=5^15

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Add. 4 7/12+2 3/4+7 5/12

mihalych1998 [28]

Answer:

C.14¾

3 9⁄10

Step-by-step explanation:

$\frac{4}{5} + 3 \frac{1}{10} = \frac{8}{10} + 3 \frac{1}{10} = 3 \frac{9}{10}$

$4 \frac{7}{12} + 2 + \frac{3}{4} + 7 \frac{5}{12} = 13 \frac{12}{12} + \frac{3}{4} = 14 + \frac{3}{4} = 14 \frac{3}{4}$

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2 years ago

X2 – 3x + 10<br><br> What is the answer to this?

Tpy6a [65]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

You bike 1 mile the first day of your training, 1.3 miles the second day, 1.9 miles the third day, and 3.1 miles the fourth d

JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

$d_1=1 mi$ is the distance travelled during the 1st day

$d_2=1.3 mi$ is the distance travelled during the 2nd day

$d_3=1.9 mi$ is the distance travelled during the 3rd day

$d_4=3.1 mi$ is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

$d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2$

Which can be rewritten using the general formula:

$d_{n+1}-d_n=2(d_n-d_{n-1})$

This means that

$d_{n+1}=d_n+2(d_n-d_{n-1})$

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

$d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi$

So, the distance travelled on the 7th day is 19.9 miles.

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3 years ago

Simplify Rewrite the expression in the form 5 ^ n. (5/10)/(5/12) =

Amiraneli [1.4K]

Answer:

$5^{-2}$

Step-by-step explanation:

$5^{(10-12)}$

5 0

3 years ago