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max2010maxim [7]

3 years ago

15

A group of friends share cost of their party. If each pays $42, there is surplus of $19.

2 answers:

Nutka1998 [239]3 years ago

7 0

61+48=109 but that's the cost for both questions but I think its right yw hope that helped :)

42+19=61

40+8=48

Serjik [45]3 years ago

3 0

If each person pays $2 more and then the difference is 27, then the number of people is 13.5! (Weird I know)
13.5 x 42 = 567
13.5 x 40 = 540

567-19 = 548
540+8 = 548

Therefore the price is $548

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Each saddle has exactly two saddle bags on it

neonofarm [45]

So we have 22 riders....each carrying 2 saddle bags.....thats (2 * 22) = 44 bags.....each saddle bag has 3 waters....(44 * 3) = 132 total water bottles

4 0

3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

(3a^2+b^4)^3/ 2a^3 b^3) ^2

mezya [45]

(Answer included in imagine)

3 0

2 years ago

I tried and now i need help

Svetradugi [14.3K]

I'm guessing the answer is B? I tried to isolate r and I got that result. Sorry if it's wrong!

3 0

3 years ago

Look at the line graphed below. Write an equation of a different line that has the same y- Entercept as the line shown, but has

AlekseyPX

Supposing the line graphed is y = 2x + 3, the equation of the different line is:

y = 4x + 3.

<h3>What is a linear function?</h3>

A linear function is modeled by:

$y = mx + b$

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.

b is the y-intercept, which is the value of y when x = 0.

In this problem, the equation is:

y = 2x + 3

Hence, the slope is 2 and the y-intercept is 3. For the new line, we want to:

Double the slope, hence m = 4.

Keep the same y-intercept, hence b = 3.

Then, the equation of the different line is:

y = 4x + 3.

You can learn more about the equation of a line at brainly.com/question/24685547

8 0

3 years ago