1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arada [10]
3 years ago
6

About 21 out of 25 Texans live in An urban area

Mathematics
1 answer:
Hoochie [10]3 years ago
8 0

Answer:

I'm confused. Is there more to the question?

You might be interested in
If the length of the base of a triangle is
Anarel [89]

Answer:

d

Step-by-step explanation:

the answer is 12% decrease in area

5 0
3 years ago
A line graph does NOT:
Vanyuwa [196]
<span>Use percentages to display data



Hope this helps.
</span>
8 0
4 years ago
How much simple interest is earned on $4,000 in 3 1/2 years at an interest rate of 5.2%?
AveGali [126]

Answer:

$728

Step-by-step explanation:

The formula for simple interest is I = PRT, where I = interest earned/paid, P = principal amount deposited or borrowed, R = rate of interest as a decimal, and T = time in years.

I = PRT

I = (4000)(0.052)(3.5)

I = 728

4 0
3 years ago
Read 2 more answers
Forty percent of households say they would feel secure if they had $50,000 in savings. you randomly select 8 households and ask
Kay [80]

Answer:

Let X be the event of feeling secure after saving $50,000,

Given,

The probability of feeling secure after saving $50,000, p = 40 % = 0.4,

So, the probability of not  feeling secure after saving $50,000, q = 1 - p = 0.6,

Since, the binomial distribution formula,

P(x=r)=^nC_r p^r q^{n-r}

Where, ^nC_r=\frac{n!}{r!(n-r)!}

If 8 households choose randomly,

That is, n = 8

(a) the probability of the number that say they would feel secure is exactly 5

P(X=5)=^8C_5 (0.4)^5 (0.6)^{8-5}

=56(0.4)^5 (0.6)^3

=0.12386304

(b) the probability of the number that say they would feel secure is more than five

P(X>5) = P(X=6)+ P(X=7) + P(X=8)

=^8C_6 (0.4)^6 (0.6)^{8-6}+^8C_7 (0.4)^7 (0.6)^{8-7}+^8C_8 (0.4)^8 (0.6)^{8-8}

=28(0.4)^6 (0.6)^2 +8(0.4)^7(0.6)+(0.4)^8

=0.04980736

(c) the probability of the number that say they would feel secure is at most five

P(X\leq 5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)

=^8C_0 (0.4)^0(0.6)^{8-0}+^8C_1(0.4)^1(0.6)^{8-1}+^8C_2 (0.4)^2 (0.6)^{8-2}+8C_3 (0.4)^3 (0.6)^{8-3}+8C_4 (0.4)^4 (0.6)^{8-4}+8C_5(0.4)^5 (0.6)^{8-5}

=0.6^8+8(0.4)(0.6)^7+28(0.4)^2(0.6)^6+56(0.4)^3(0.6)^5+70(0.4)^4(0.6)^4+56(0.4)^5(0.6)^3

=0.95019264

8 0
3 years ago
21) Find x. Show your work.
shepuryov [24]

Answer:

x = 21

Step-by-step explanation:

Givens:

Every triangle's interior angles add up to 180°

The triangle has a right angle.

The triangle is isosceles (two equal sides and two equal angles)

Let's make an equation with the information we have already.

2 × (2x + 3) + 90 = 180

4x + 6 + 90         = 180

4x + 96                = 180

4x                         = 84

x                           = 21

4 0
3 years ago
Other questions:
  • You are ima room with other students and are asked to get in groups of 3. When finished, there are 21 groups of 3. How manny stu
    12·2 answers
  • What is y-5+3-9(y+2) and the work to go with it
    9·2 answers
  • ntervals of Hundredths (3.30)2 10.89 (3.31)2 10.96 (3.32)2 11.02 (3.33)2 11.09 (3.34)2 11.16 (3.35)2 11.22 (3.36)2 11.29 (3.37)2
    7·2 answers
  • What is 0.009% of 5000? Round to the nearest hundredth (if necessary).
    8·2 answers
  • GIVING 20 POINTS I NEED IT ASAP
    15·1 answer
  • Nth term sequences, please may I get some help. 15 p.
    9·1 answer
  • Triangle ABC has coordinates of A(–8, –8), B(4, –2), and C(2, 2). Find the coordinates of its image after a dilation centered at
    10·2 answers
  • Find the areas of the trapezoid<br> Due soon! I WILL GIVE BRAINLIEST!! WORTH 46 points (92 total)
    6·2 answers
  • La derivada de f(x)=3x^2-5x+2
    8·2 answers
  • Please help! The question is in the image
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!