About 21 out of 25 Texans live in An urban area

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match the system of equations with their so

allochka39001 [22]

Answer:

Part 1) solution {(-5,8),(3,0)} ----> $y+12=x^{2}+x$ and $x+y=3$

Part 2) No solutions ----> $y-15=x^{2}+4x$ and $x-y=1$

Part 3) solution [(-2,5),(3,-5)] ---> $y+5=x^{2}-3x$ and $2x+y=1$

Part 4) No solutions ---> $y-6=x^{2}-3x$ and $x+2y=2$

Part 5) solution [(2,3),(8,9)] ---> $y-17=x^{2}-9x$ and $-x+y=1$

Part 6) solution [(-2,3),(7,-6)] ---> $y-15=-x^{2}+4x$ and $x+y=1$

Step-by-step explanation:

Part 1) we have

$y+12=x^{2}+x$ ----> equation A

$x+y=3$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-5,8) and (3,0)

see the attached figure N 1

Part 2) we have

$y-15=x^{2}+4x$ ----> equation A

$x-y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs

see the attached figure N 2

Part 3) we have

$y+5=x^{2}-3x$ ----> equation A

$2x+y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,5) and (3,-5)

see the attached figure N 3

Part 4) we have

$y-6=x^{2}-3x$ ----> equation A

$x+2y=2$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs

see the attached figure N 4

Part 5) we have

$y-17=x^{2}-9x$ ----> equation A

$-x+y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (2,3) and (8,9)

see the attached figure N 5

Part 6) we have

$y-15=-x^{2}+4x$ ----> equation A

$x+y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,3) and (7,-6)

see the attached figure N 6

5 0

3 years ago

Suppose there are n independent trials of an experiment with k3 mutually exclusive outcomes, where pi represents the probabilit

sasho [114]

Complete question :

Suppose there are n independent trials of an experiment with k > 3 mutually exclusive outcomes, where Pi represents the probability of observing the ith outcome. What would be the formula of an expected count in this situation?

Answer: Ei = nPi

Step-by-step explanation:

Since Pi represents the probability of observing the ith outcome

The number of independent trials n = k>3 :

Expected outcome of each count will be the product of probability of the ith outcome and the number of the corresponding trial.

Hence, Expected count (Ei) = probability of ith count * n

Ei = nPi

8 0

3 years ago

What’s does 120$ plus 40% mean

Fynjy0 [20]

Answer:

ur suppose to find how much it is after the discount so for example in question 1 the discount is 40% so subtract that from 100% to get 60% then multiply this 60% by the origanial vaule which is 120 so for the answer for question 1 would be 72. Also when multiplying 60% u dont multiply by 60 u multiply it by 0.6

Hope this help and sry for the bad grammar

3 0

2 years ago

Please help!! If f (x) = e^x sin x, then f’ (x) =

shusha [124]

Answer:

$f'(x) = {e}^{x}( \sin x + \cos x )$

Step-by-step explanation:

$f(x) = {e}^{x} \sin x \\ \\ f'(x) = \sin x \frac{d}{dx} {e}^{x} + {e}^{x} \frac{d}{dx} \sin x \\ \\ f'(x) = \sin x \: {e}^{x} +{e}^{x} \cos x \\ \\ f'(x) = {e}^{x}( \sin x + \cos x )$

5 0

3 years ago

4×..., biar jadi 100...<br><br><br>tolong ya kak...

ladessa [460]

Answer:

25

Step-by-step explanation:

4×25 =100

____________

8 0

3 years ago