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liberstina [14]
3 years ago
12

The letters for the word SCHOOL are placed in a hat. What is the probability of drawing the letter O out of the hat?

Mathematics
2 answers:
Oduvanchick [21]3 years ago
6 0

Answer:

I think it would be 2/6 or 33.33%

cluponka [151]3 years ago
3 0
This would be 2/6 chances or percentage form about 33%
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Of 250 seventh grade students, 130 walk to school. What percent of seventh graders do not walk to school? % of seventh graders d
Bad White [126]

Answer:

48%

Step-by-step explanation:

I like to look at percentages as test grades. If you got a 130/250 on a test, you would simply need to view the dash line as a 'divided by'. So you would figure 130 divided by 250 is .52, or 52%... Then, you would need to subtract 52 from 100 to get 48% to get the percentage of people who do not walk to school.

7 0
2 years ago
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Estimate the sum or difference 4/5+18/20 A 1 B 1 ,1/2 C 2
const2013 [10]

Answer:

C 2

Step-by-step explanation:

4/5+18/20=1.7

Round that up it’s 2

6 0
3 years ago
The equation Y-3=-2(x+5) is written in point-slope form. What is the y-intercept of the line?
xz_007 [3.2K]

Answer:

Step-by-step explanation:

hello :

y-3=-2(x+5)

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7 0
3 years ago
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Calculate the annual interest for a $10,000 Treasury bond with a current yield of 3% that is quoted at 106 points.
Sergio [31]

Answer:

$318

Step-by-step explanation:

The treasury bond is $10,000

The current yield is 3%

= 3/100

=0.03

It is quoted at 106 points

The first step is to calculate the price of the bond

Price of the bond= $10,000×106/100

= $10,000×1.06

= $10,600

Therefore the annual interest can be calculated as follows

Annual interest= $10,600×0.03

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Hence the annual interest is $318

7 0
3 years ago
Suppose that the hourly wages of fast food workers are normally distributed with an unknown mean and standard deviation. The wag
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Step-by-step explanation:

The t-score for a level of confidence (1-\alpha) is given by :_

t_{(df,\alpha/2)}, where df is the degree of freedom and \alpha is the significance level.

Given : Level of significance : 1-\alpha:0.80

Then , significance level : \alpha: 1-0.80=0.20

Sample size : n=40

Then , the degree of freedom for t-distribution: df=n-1=40-1=39

Using the normal t-distribution table, we have

t_{(df,\alpha/2)}=t_{39,0.10}=1.303639

Thus, the t-score should be used to find the 80% confidence interval for the population mean =1.303639

8 0
3 years ago
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