"a farmer bought the same number of calves and cows for 476,000. He/she paid 800 for a calf and 2000 for a cow, how many animals of each species did he/she buy?"

<h2>Solution to the problem</h2>

1. Choose the variable's name and translate the verbal statements into algebraic expressions:

a) number of calves or cows: x

b) He/she paid 800 for a calf: 800x

c) He/she paid 2,000 for a cow: 2000x

d) For 476,00: 800x + 2000x = 476,000 . . . . this is your equation

2. Solve the equation:

a) Write the equation:

$800x+2,000x=476,000$

b) Add like terms:

$2,800x=476,000$

c) Use division property of equalities: divide both sides by 800:

$x=476,000/2,800=170$

d) Translate the solution into a verbal statement:

Since x represents both the number of calves and the number of cows, the answer is:

The farmer bought 170 animals of each species.

6 0

3 years ago

Jerome is planning a fundraiser.

PilotLPTM [1.2K]

Answer:132

Step-by-step explanation: 1.25-.50=75 the profit of each apple is 75 cents

99 dollars divided by .75 is 132

8 0

3 years ago

Find the equation Of the line that is parallel to the line negative 3X plus 2Y equals 10 and go to the .0, seven

lesya692 [45]

Answer:

3x+2Y=10

6×-5-1×=0

Step-by-step explanation:

6-5-1=0

5 0

3 years ago