The answer to this is true.
ANSWER: no two elements would have the same number of protons, hope this helps
Answer:
3
Explanation
N is 14, so multiply it by 6 (because 6 moles). Since it's N2, divide it by 2, then divide it by 14 (N in grams).
You may find the electron diagram of ammonia and the ammonium ion in the attached picture.
Explanation:
Ammonia NH₃ have covalent bonds with the hydrogen atoms in which for each bond one electron comes from nitrogen atom (blue dot) and the other from the hydrogen atom (red dot). You may see that the nitrogen remains with the lone pair of electrons that does not participate in bonding.
Ammonia NH₃ have a basic character and is able to accept a proton H⁺ from an acid to form the ammonium ion NH₄⁺. The fourth bond formed its called a coordinative-covalent bond that is created only with the nitrogen lone pair of electrons (blue dots).
Learn more about:
ammonium ion
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Answer: -
12.59
Explanation: -
Strength of NaOH = 0.0179 M
Volume of NaOH = 58.0 mL = 58.0/1000 = 0.058 L
Number of moles = 0.0179 M x 0.058 L
= 1.04 x 10⁻³ mol
Mol of [OH⁻] given by NaOH = 1.04 x 10⁻³ mol
Strength of Ba(OH)₂ = 0.0294 M
Volume of Ba(OH)₂ = 60.0 mL = 60.0/1000 = 0.060 L
Number of moles = 0.0294 M x 0.060 L
= 1.76 x 10⁻³ mol
Mol of [OH⁻] given by Ba(OH)₂ =2 x 1.76 x 10⁻³ mol
Total [OH⁻] = 1.04 x 10⁻³ mol + 2 x 1.76 x 10⁻³ mol
= 4.56 x 10⁻³ mol
Total volume of the mixture = 58.0 + 60.0
= 118.0 mL
118.0 mL of the solution has 4.56 x 10⁻³ mol [OH⁻]
1000 mL of the solution has 
= 0.0386 mol
Using the relation
pOH = - log [OH-]
= - log 0.0386
= 1.41
Using the relation
pH + pOH = 14
pH = 14 - 1.41
= 12.59