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Ira Lisetskai [31]
1 year ago
6

Which is responsible for the formation of rust on metals?(1 point)

Chemistry
1 answer:
Rainbow [258]1 year ago
5 0

The correct answers about rusting, air pollution and products of water with rock are:

Option A. oxidation

Option D. Pollutants mix with air and water to make acid rain.

Option B. clay minerals and calcium carbonate

<h3>What is rusting?</h3>

Rusting is the process by which a metal especially reacts with oxygen in the atmosphere and water vapor to form a hydrated oxide of the metal known as hydrated iron (iii) oxide. This is known as rust.

The process is an oxidation process; option A.

<h3>How does air pollution impact chemical weathering?</h3>

Air pollution is the presence of substances in air known as pollutants which makes the air impure.

Air pollution impact chemical weathering  as the pollutants mix with air and water to make acid rain which weathers rocks; option D.

<h3>What products are produced when water reacts with sodium in rocks?</h3>

The reaction of water with sodium in rocks result in the formation of clay minerals and calcium carbonate also as limestone, marble or chalk; option B.

In conclusion, the presence of pollutants in air results in acid rain and hence rock weathering.

Learn more rock weathering at: brainly.com/question/2341950

#SPJ1

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Emily spills concentrated sodium hydroxide solution on her lab bench. What she should do first?
blagie [28]
<h2>Answer:</h2>

She should notify her teacher.

<h2>Explanation:</h2>

Sodium Hydroxide is very corrosive in nature and it causes Redness, Pain, Serious skin burns and Blisters. Sodium hydroxide does not produce systemic toxicity, but is very CORROSIVE and can cause severe burns in all tissues that it comes in contact with. Therefore she should not touch it and she must notify her teacher as soon as possible.

4 0
2 years ago
A mixture of gases contains 4.46 moles of neon (Ne), 0.74 mole of argon (Ar), and 2.15 moles of xenon (Xe). Calculate the partia
viva [34]

Explanation:

The partial pressure of an individual gas is equal to the total pressure of the mixture multiplied by the mole fraction of the gas.

Total pressure = 2atm

Mole Fraction = number of moles / total number of moles

Neon

Mole Fraction = 4.46 / 7.35 = 0.607

Partial Pressure = 0.607 * 2 = 1.214 atm

Argon

Mole Fraction = 0.74 / 7.35 = 0.101

Partial Pressure = 0.101 * 2 = 0.202 atm

Xenon

Mole Fraction = 2.15 / 7.35 = 0.293

Partial Pressure = 0.293 * 2 = 0.586 atm

5 0
3 years ago
Type the correct answer in the box.
IgorLugansk [536]

Answer:

a= <em>In scientific notation</em>

6.96000×10⁵ Km

b =<em>In  expanded notation</em>

0.00019 mm

Explanation:

Given data:

Radius of sun = 696000 Km

size of bacterial cell = 1.9 ×10⁻⁴ mm

Radius of sun in scientific notation = ?

Size of bacterial cell in expanded notation = ?

Solution:

Scientific notation is the way to express the large value in short form.

The number in scientific notation have two parts.

. The digits (decimal point will place after first digit)

× 10 ( the power which put the decimal point where it should be)

for example the number 6324.4 in scientific notation will be written as = 6.3244 × 10³

Radius of sun:

696000 Km

<em>In scientific notation</em>

6.96000 × 10⁵ Km

The expanded notation is standard notation of writing the numerical values which is normal way. The numbers are written as they are, without the power of 10.

Size of bacterial cell:

1.9 ×10⁻⁴ mm

<em>In  expanded notation</em>

1.9/ 10000 = 0.00019 mm

3 0
3 years ago
The chemistry of life is centered on the chemistry of the element oxygen. True False
Artyom0805 [142]
I believe the answer is true, Hope i helped! :)<span />
7 0
3 years ago
Read 2 more answers
A 5.00 L sample of air at 0 C is warmed to 100.0 C. What is the new volume of the air? First, identify V1.
Paladinen [302]

Answer : The new volume of the air is, 6.83 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=5.00L\\T_1=0^oC=(0+273)K=273K\\V_2=?\\T_2=100^oC=(100+273)K=373K

Putting values in above equation, we get:

\frac{5.00L}{273K}=\frac{V_2}{373K}\\\\V_2=6.83L

Therefore, the new volume of the air is, 6.83 L

6 0
3 years ago
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