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2 years ago

6

−px+r=−8x−2 solve for x Plx I need this ASAP

1 answer:

svet-max [94.6K]2 years ago

3 0

Answer:

x= $\frac{2+r}{p-8\\}$

Step-by-step explanation:

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What is the solution to the system of equations below? Y=-4/5x-6 & y=-30

Ainat [17]

So when you are trying to find the solution to the system of equations make sure that you have it where y= -4/5x-6 and y= -30 are written like this:

-30=-4/5x-6

And then solve for x:

Add 6 on both sides.

-24=-4/5x

Then multiply by the reciprocal of -4/5.

-5/4*-24=-5/4*-4/5x

x=30

But then you are gonna want to plug 30 in for x in y=-4/5x-6 to make sure that it is the same as y=-30.

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slavikrds [6]

ANSWER

$y=-\frac{4}{3}x+\frac{16}{3}$

Or

$3y+4x=16$

EXPLANATION

Let us find the gradient of the line:

$-3x+4y=4$ by rewriting it in the slope intercept form.

$\Rightarrow 4y=3x+4$

We divide through by 4 now;

$\Rightarrow y=\frac{3}{4}x+1$

This is now in the form;

$y=mx+c$

where

$m=\frac{3}{4}$ is he slope.

This implies that the slope of the line that is perpendicular to this line will be the negative reciprocal of $m=\frac{3}{4}$ .

Thus the perpendicular line has slope,

$m=\frac{-1}{\frac{3}{4}}= -\frac{4}{3}$ .

Let the perpendicular line have equation,

$y=mx+c$

When we substitute the slope we have;

$y=-\frac{4}{3}x+c$

We substitute the point. $(4,0)$ to find c.

$0=-\frac{4}{3}(4)+c$

$0=-\frac{16}{3}+c$

$\frac{16}{3}=c$

We substitute c to obtain;

$y=-\frac{4}{3}x+\frac{16}{3}$

Or

$3y+4x=16$

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