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Semmy [17]
3 years ago
6

−px+r=−8x−2 solve for x Plx I need this ASAP

Mathematics
1 answer:
svet-max [94.6K]3 years ago
3 0

Answer:

x=\frac{2+r}{p-8\\}

Step-by-step explanation:

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What step of the design process is this: “Used the test results to identify any modifications that they needed to make to improv
sergiy2304 [10]

I dont know how to answer this question

4 0
3 years ago
Find the equation of the line that passes through (-1, 4) and is perpendicular to the
statuscvo [17]
For perpendicular lines, m2 = -1/m1; where m1 is the slope of line 1 and m2 is the slope of line 2.
m1 = (-4 - 2)/(4 - 2) = -6/2 = -3
m2 = -1/-3 = 1/3
Equation of the required line is given by: y - 4 = 1/3 (x - (-1))
y - 4 = 1/3 x + 1/3
y = 1/3 x + 1/3 + 4
y = 1/3 x + 13/3
6 0
3 years ago
Cayenne bought 20 pencils for 1.60 dollars at that rate how much would 35 pencils cost ​
yanalaym [24]
35 pencils would cost $2.80,


$1.60 / 20 = $.08
Each pencil costs $0.08 each

.08 * 35 = 2.80
4 0
3 years ago
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
8 0
3 years ago
Explain how do you know that 712 is greater than 1/3 but less than 2/3
Rudik [331]

Answer:

712 is bigger than 1/3 and 2/3.

Step-by-step explanation:

Because it is whole number, while 1/3 and 2/3 are fraction of whole number.

Did you mean 7/2?

5 0
3 years ago
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