The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
What is the intermediate value theorem?
Intermediate value theorem is theorem about all possible y-value in between two known y-value.
x-intercepts
-x^2 + x + 2 = 0
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1, x = 2
y intercepts
f(0) = -x^2 + x + 2
f(0) = -0^2 + 0 + 2
f(0) = 2
(Graph attached)
From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3
For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.
<em>Your question is not complete, but most probably your full questions was</em>
<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>
Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
Learn more about intermediate value theorem here:
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0.5 is above because that .5 of a change is keeping the water from freezing because it is still slightly babouche freezing point.
-13 is below because the number is a negative so is below 0 anyway and is below the freezing point.
100 is above because the number 100 is higher than 0 so it’s above freezing point.
5.5 is above because it is a larger number than the freezing point so the water would not freeze yet at this temperature.
-2.25 is below because it’s a negative number.
I think that’s what you meant not 100% sure but that’s how I would do it :)
Y=3x+7
this equation is in slope- intercept form (y=mx+b), so to translate up or down you add or subtract however many units you are translating to the b of the equation.
Answer:
ans=(-2,2)
Step-by-step explanation:
let the end point of circle diameter (-1,5) and (3,-1) be (x1,y1) and (x2,y2) respectively
using mid point formula
(x,y)=(-1,5)/2+(-3,-1)/2 [center point is equal to mid point of diameter)
= (-1+(-3))/2+(5-1)/2
=(-2,2)
center coordinate of circle=(-2,2)